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dolphi86 [110]
3 years ago
13

Find an equation for the line that a) is parallel to the line defined by y = 2x + 3 and passes through the point (4, 5)

Mathematics
1 answer:
drek231 [11]3 years ago
8 0

Answer:


Step-by-step explanation:


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Write at least three equivalent names for 9%
Svetradugi [14.3K]
0.09
9/100
nine hundreths
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4 years ago
What is the midpoint of a segment whose endpoints are (14,-7) and (6,-7)?
Alekssandra [29.7K]
(10, -7) is the midpoint
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3 years ago
Find the common ratio of the geometric sequence: −320,80,−20,5,…−320,80,−20,5,… A. −14−14 B. 1414 C. -4 D. 4
vredina [299]
I'm assuming the sequence is: -320, 80, -20, 5

Divide each term by the previous term to get the common ratio r

r = (term 2)/(term 1) = 80/(-320) = -1/4
r = (term 3)/(term 2) = -20/80 = -1/4
r = (term 4)/(term 3) = 5/(-20) = -1/4

No matter which term you pick (as long as it's not the first one) dividing it by the previous term leads to -1/4 or -0.25 as the common ratio

Answer: -1/4

It seems like none of the answer choices have -1/4 but it could be choice A was supposed to show "-1/4" instead of "-14"? Perhaps the division sign didn't show up for some reason?

3 0
3 years ago
Find the second, fourth, and eleventh terms of the sequence A(n) = 5 + (n - 1)(-3)​
klio [65]

Answer:

2nd: 2

4th: -4

11th: -25

Step-by-step explanation:

When you substitute a number into the equation you get that number term. So, if you substituted in 1, you get the first term. To find the second term, you substitute in 2:

A(2) = 5 + (2 - 1)(-3)

A(2) = 5 + (1)(-3)

A(2) = 5 - 3

A(2) = 2

To get the 4th term you substitute in 4:

A(4) = 5 + (4 - 1)(-3)

A(4) = 5 + (3)(-3)

A(4) = 5 - 9

A(4) = -4

And we do the same for the 11th term:

A(11) = 5 + (11 - 1)(-3)

A(11) = 5 + (10)(-3)

A(11) = 5 - 30

A(11) = -25

8 0
3 years ago
Help me plssssssssssssss
siniylev [52]

Answer:

yes

Step-by-step explanation:

why do you need this silly boy

6 0
3 years ago
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