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2 years ago

Solve for x in simmilar triangles connected

Mathematics

1 answer:

amid [387]2 years ago

6 0

Step-by-step explanation:

You can figure out the missing side length by using proportions because the corresponding side lengths form a proportion. Let's write ratios that form a proportion and find the pattern to figure out the length of the missing side. Looking at this you can see the pattern

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Please help ( if you can then please help with <br> both questions )

tatuchka [14]

Answer:

For number 1, -1.125 and -9/8. For number 2, -46.

Step-by-step explanation:

6 0

2 years ago

Write the expression 5x+2x^2-7+2x^3

avanturin [10]

2x^3+2x^2+5x-7, That would be the answer.

3 0

3 years ago

A survey found that 89% of a random sample of 1024 American adults approved of cloning endangered animals. Find the margin of er

Kobotan [32]

Answer:

The margin of error for the survey is 0.016

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1024

Sample proportion:

$\hat{p} = 89\% = 0.89$

We have to find the margin of error associated with a 90% Confidence interval.

Formula for margin of error:

$z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.10} = 1.64$

Putting the values, we get:

$M.E = 1.64\times (\sqrt{\dfrac{0.89(1-0.89)}{1024}})\\\\M.E=0.016$

Thus, the margin of error for the survey is 0.016

3 0

3 years ago

Find a. Round to the nearest tenth:

marusya05 [52]

Answer:

14.356

Step-by-step explanation:

that's the answer round up to 14.4

5 0

2 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

4 0

1 year ago