2x+4\x^2+4x+3 divided by x^2-4/x+1

Mathematics

1 answer:

attashe74 [19]3 years ago

4 0

Remember
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

so
first factor them
$( \frac{2(x+2)}{(x+1)(x+3)} )( \frac{(x-2)(x+2)}{x+1} )$ =
$( \frac{2(x+2)}{(x+1)(x+3)} )( \frac{x+1}{(x-2)(x+2)} )$ =
$\frac{2(x+2)(x+1)}{(x+1)(x+3)(x-2)(x+2)}$ =
factor out ones
$( \frac{2}{(x+3)(x-2)} )( \frac{(x+2)(x+1)}{(x+2)(x+1)} )$ =
$( \frac{2}{(x+3)(x-2)} )(1)$ =
$\frac{2}{(x+3)(x-2)}$ =
$\frac{2}{x^2+x-6}$

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