1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klemol [59]
3 years ago
15

the temperature of a pot of water fell from 72°F to 36°F in 4 minutes. find the average temperature per minute

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
If the temperature falls from 72°F to 36°F in four minutes, it means it fell 72-36 = 36°F in four minutes.

To find out what's the value of the temperature fall in one minute we just have to divide 36 by 4:

36 / 4 = 9

Answer: The temperature fell 9°F per minute.
Snowcat [4.5K]3 years ago
7 0

Answer:

Average temperature = 9°F per minute

Step-by-step explanation:

Given : the temperature of a pot of water fell from 72°F to 36°F in 4 minutes.

To find : Find the average temperature per minute.

Solution : We have given

Temperature decreases in 4 minute =  72°F to 36°F

72 -36 = 36°F

Temperature decreases in 4 minute =  36°F

Temperature decreases in 1 minute =  \frac{36}{4}.

Temperature decreases in 1 minute =  9°F

Average temperature =  \frac{9}{1}.

Average temperature = 9°F per minute.

Therefore,  Average temperature = 9°F per minute.

You might be interested in
Identify the inequality that corresponds to the graph below. Choose all that apply.
mrs_skeptik [129]
The answer is a because it is open circle
7 0
3 years ago
jackie’s report is 5 pages longer than half the number of pages in kane’s report. there are 14 pages in kane’s report. how many
Vitek1552 [10]
Oh! I answered this question last week! Don't know if it was the same exact one, but whatever. So first cut the number of pages in Kate's report in half, then add 5 to that. So, (14÷2)+5
6 0
3 years ago
Read 2 more answers
What describes angle 5 and 6
astraxan [27]

Answer:

Your answer is B: Corresponding angles.

4 0
3 years ago
Read 2 more answers
Answer correct please
natita [175]

Answer:

correct

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please solve the following quadratic equation and show your work: x^2 -x =30
saveliy_v [14]
Rewriting the equation as a quadratic equation equal to zero:
     x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
     (x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
     x + 5 = 0  => x = -5
     x - 6 = 0  => x = 6
Therefore, our solutions are x = -5 and x = 6.
8 0
3 years ago
Other questions:
  • in a survey 8 out of 32 students preferred vanilla ice cream if 252 students are surveyed how many should theoretically prefer v
    8·1 answer
  • Harita must memorize 90 measures of music for her cello solo at a concert. She plans on memorizing 18 new measures for every 3 d
    8·2 answers
  • In ΔABC, m∠B = 90°, , and AB = 26 units.Based on this information, m∠A = °, m∠C = °, and AC = units.
    7·1 answer
  • All of the following represent three multiplied by six except:<br> 3x6<br> 3.6<br> 316)<br> 3:6
    6·1 answer
  • Raina buys candy that costs $7 per pound. She will buy less than 11 pounds of candy. What are the possible amounts she will spen
    6·1 answer
  • (b) Jac thinks of a number,<br> 25% of his number is 35.<br> What is 1/10 of Jac's number?
    12·1 answer
  • What is the slope of a trend line that passes through the points (1, 3) and (10, 25)?
    9·1 answer
  • Let f(x) = 5x + 2 and g(x) = x² + 2x + 5. Evaluate the following.
    13·1 answer
  • Solve the short line equation, image attached, giving brainliest please help
    5·1 answer
  • Rewrite the following in radical form <br> X^-11/3
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!