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2 years ago

Write a rule to describe the transformation

Mathematics

1 answer:

Brut [27]2 years ago

8 0

Translating 4 units to the right then reflecting over the x axis

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PLEASE HELP

Bezzdna [24]

Answer:

D. 3x-8=16

Step-by-step explanation:

Eight less (-8) than 3 times a number (3x) equals sixteen (16).

4 0

3 years ago

A 4-pack of batteries costs $5.16. At this price, what is the cost of one battery?

antiseptic1488 [7]

Answer:

$1.29

Step-by-step explanation:

5.16 divided by 4

8 0

4 years ago

The radius of a semicircle is 18 kilometers. What is the semicircle's area?

Sergio039 [100]

Answer:

Area of a semi circle is 1/2πr²

r = radius

Area = 1/2 × π × 18²

= 162π

= 508.94km²

Hope this helps.

8 0

3 years ago

Read 2 more answers

X=(1/1+2) (8+6) + -6

Sidana [21]

If we are finding x it would be 36

7 0

3 years ago

(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)

Elena L [17]

Answer:

$\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\$

Step-by-step explanation:

$\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1} }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}$

$= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3} - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3} - 36a^{2} - 36 - 12a)} {2a+1}$

$= \frac{144a^{4}+36a^{2}+144a^{3} - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\$

6 0

4 years ago