What is the <br> Quadratic form for (-1,-11) (0,-3) (3,-27)

I need help for algebra 2 for simplify form for example (3x-2i)(3x+2i)

grandymaker [24]

Let's start...

$(3x-2i)*(3x+2i)$

$3x*3x+3x*2i-2i*3x-2i*2i$

$9x^2+6xi-6xi-4i^2$

$9x^2-4i^2$

we don't finish it yet...

$i^2=-1$

Let's replace it

$9x^2-4*(-1)$

$\boxed{\boxed{9x^2+4}}$

6 0

3 years ago

Read 2 more answers

Find the set of solutions for the linear system.

Illusion [34]

Answer:

The system has infinitely many solutions.

$\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9} \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3} \\x_4&=&s_2\end{array}\right$

Step-by-step explanation:

To find the solution for this system of linear equations $-3x_1-x_2+4x_3=2\\-3x_3 - 4x_4 = -1$ you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

A matrix is a rectangular arrangement of numbers into rows and columns.

A system of equations can be represented by an augmented matrix.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is matrix that represents the system

$\left[ \begin{array}{ccccc} -3 & -1 & 4 & 0 & 2 \\\\ 0 & 0 & -3 & 4 & -1 \end{array} \right]$

The augmented matrix can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

Interchange two rows (or columns).
Multiply each element in a row (or column) by a non-zero number.
Multiply a row (or column) by a non-zero number and add the result to another row (or column).

Using elementary matrix operations, we get that

Row Operation 1: Multiply the 1st row by -1/3

Row Operation 2: Multiply the 2nd row by -1/3

Row Operation 3: Add 4/3 times the 2nd row to the 1st row

$\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]$

Step 2: Interpret the reduced row echelon form

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]$

which corresponds to the system

$x_1+\frac{1}{3}x_2+ \frac{16}{9}x_4=-\frac{2}{9} \\x_3+ \frac{4}{3}x_4=\frac{1}{3}$

We see that the variables $x_2, x_4$ can take arbitrary numbers; they are called free variables. Let $x_2=s_1$ , $x_4=s_2$ . All solutions of the system are given by

$\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9} \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3} \\x_4&=&s_2\end{array}\right$

The system has infinitely many solutions.

8 0

4 years ago

100 POINTS IF YOU ANSWER CORRECTLY Rotate these coordinates 180 around the origin and then translate 6 units to the left.

snow_tiger [21]

Original Coordinates: (-2, -8) (-6, -8) (-11, -1) (-7, -3)

A 180 degree rotation around the origin flips the signs of x and y, so you get:

(2, 8) (6, 8) (11, 1) (7, 3)

Then a translation to the left 6 units just subtracts 6 from all the x values:

(-4, 8) (0, 8) (5, 1) (1, 3)

Those are your points! Hope this helped!

8 0

4 years ago

Read 2 more answers

Please answer all the questions below <br> Thanks

Lera25 [3.4K]

F= 1.333...
c= - 3.2
g = -9

8 0

3 years ago

3x-1 and 5x+2 find the area

Alex787 [66]

Answer:

$= 15 {x}^{2} + x - 2 \\$