Answer:
You always do the X-axis first. Hope this helps! :)
<h3>
CloutAnswers</h3>
Here we have a problem of probability, we will find that the probability of landing in heads is M/N = 1/3, then we have:
M + N = 1 + 3 = 4.
Let's see how we got that:
Let's define:
p = probability of landing on tails
q = probability of landing on heads.
The probability of getting at least one tails in 3 tosses is 26/27
This means that the probability of not getting tails in the 3 tosses is:
P = 1 - 26/27 = 1/27
And the case where you do not get any tails in the 3 tosses, means that in all the 3 tosses you got heads.
The probability of getting 3 heads in a row is:
P = q^3 = 1/27
Solving for q, we get:
q = ∛(1/27) = 1/3
Now we want to express q = M/N = 1/3
then we have:
M = 1
N = 3
Now we want to compute M + N = 1 + 3 = 4
If you want to learn more about probability, you can read:
brainly.com/question/24369877
Looking at number 4, you first have to look at the information that you have:
On tuesday he practiced for 1 5/6 hrs
Monday he practiced for 7/10 hrs
He is supposed to practice for 1 1/4 hr.
You could write questions like:
How much more did Marco practice on Tuesday than he is supposed to practice?
This works because it does indeed involve subtraction, you would be subtracting the amount that he should have practiced from the amount of time that he did practice.
If I didn't answer the question, please message me and I will clarify!
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90
2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10
Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b
2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10
3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100
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Answer: The numbers are 100 and 10</span>
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155
OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.
