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allochka39001 [22]
3 years ago
8

What is 1,995,298 rounded to the nearest 10,000

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0
It is 1,100,000. All you do is put the 5 up

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Please help I’ll mark you as brainliest if correct!<br><br> A<br> B<br> C<br> D
Andrei [34K]

Answer:

A is the answer

Step-by-step explanation:

8 0
3 years ago
What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)
olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.  

For example:

Type of change               Effect on y = f(x)

y = f(x - c)                      horizontal shift: c units to right

So

Considering the function

f(x) = x^2

The graph is shown below. The first figure is representing f(x) = x^2.

Now, considering the function

\:f\left(x\right)=\left(x-6\right)^2

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of \:f\left(x-6\right)=\left(x-6\right)^2 is shown below in second figure. It is clear that the graph of  \:f\left(x-6\right)=\left(x-6\right)^2  is shifted 6 units to the right as compare to the function f(x) = x^2.

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

5 0
3 years ago
Write in slope-intercept form and show work:<br> 6x + 4y = 700
Basile [38]
6x + 4y = 800
-6x -6x
--------------------
4y = -6x + 800
÷4 ÷4 ÷4
---------------------
y = -6/4x + 200

First subtract, then divide, and then you have it. 6/4 is your slope. Your rise is -6 and your run is 4.
4 0
3 years ago
Mike travels 13 miles per 2 hours on his bike.
LiRa [457]

Answer:

It took Markus half an hour to drive home from work.  He averaged 34 miles per hour.  How far does Markus live from his work?

Solution

We are given that it takes 1/2 an hour for the trip.  This is a time:

       t  =  1/2

We are given that he averages 34 miles per hour.  This is a rate:

       r  =  34

We are asked how few he has traveled.  This is a distance.  We use the d=rt equation:

       d  =  rt

           =  (34)(1/2)

           =  17

Markus lives 17 miles from work.

Now try one by yourself.  If you want to see the answer, put your mouse on the yellow rectangle and the answer will appear.

Exercise 1

The current along the beach is moving towards the south at 1.5 miles per hour.  If a piece of debris is placed into the water, how far will the current take it in 6 hours?

Step-by-step explanation:

4 0
3 years ago
The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (
sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

\dfrac{dr}{dt} = 1\text{ meter per hour}                

The height is decreasing at a rate 4 meter per hour  

\dfrac{dh}{dt} = -4\text{ meter per hour}

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

\pi r^2 h

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}

Putting all the values we get,

\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.      

3 0
3 years ago
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