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Pavel [41]
3 years ago
7

For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range.

Mathematics
2 answers:
topjm [15]3 years ago
8 0
f(x)=3(x-1)^{2}+2 \\  \\ f(x)=a(x-p)^{2}+q \\  \\ W=(p,q) \\  \\ W=(1,2) \\  \\ D: x \in R \\  \\ a \ \textgreater \ 0 \\  \\ Range: y \in [2,+\infty)

==================================
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<em>"Associate with people who are likely to improve you."</em>
KiRa [710]3 years ago
3 0
f(x)=3(x-1)^2+2\ It's\ a\ quadratic\ function\\\\therefore\ Domain:\boxed{D:x\in\mathbb{R}\ all\ real\ numbers}\\\\vertex:\\the\ vertex\ form:\ y=a(x-h)^2+k\\where\ (h;\ k)h\ and\ k\ are\ the\ x\ and\ y\ coordinates\ of\ the\ vertex\\\boxed{vertex:(1;\ 2)}
range:\\a=3 \ \textgreater \  0\ therefore\  the\ parabola\ ope ns\ upward\\so\\range\ is\ [vertex\ (y);\ infinity)\\range:\boxed{y\geq2\y\in[2;\ \infty)}\\\\Your\ answer:\\\boxed{The\ vertex\ (1;\ 2);\ domain\ is\ all\ real\ number\ (x\in\mathbb{R});\ range\ y\geq2}
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Step-by-step explanation:

She's being paid six hours per hour

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x² + 10x + 12

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Question (2)

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3 years ago
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gulaghasi [49]
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6 0
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Karolina [17]

Answer:

Part a) y=50t+70

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Step-by-step explanation:

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we know that

The linear equation in slope intercept form is equal to

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In this problem we have

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3 years ago
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valentina_108 [34]
7/9 = 0.77
-0.8
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least to greatest : -0.8, 7/9, sqrt 3
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3 years ago
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