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velikii [3]
2 years ago
10

What is the range of the following function: f(x)=-x^2+x^-1 if the domain is {-2, -1, 1}

Mathematics
1 answer:
postnew [5]2 years ago
8 0

f(x)= -x^2 + x^-1

f(-2)= - (-2)^2 + (-2)^-1 = -4 - 1/2 = -9/2

f(-1)= - (-1)^2 + (-1)^-1 = -1 -1    =   -2

f(1) = - (1)^2 + (1)^-1 = -1 +1 = 0

The range is { -9/2, -2, 0}


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Allushta [10]
Thanks for the helpful answers
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2 years ago
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postnew [5]

Answer:

(2)

Step-by-step explanation:

slope:-1/2

y-intercept:1   (because the function passes (0,1))

3 0
2 years ago
Explain why the sum 2x^2 + 4x^2<br><br>  is not equivalent to 6^4  <br>What is the correct answer?
Greeley [361]
6x^2 is the correct answer to the problem.
8 0
3 years ago
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Factor f(x) = 4x3 + 15x2 – 24x + 5 into linear factors given that - 5 is a zero of f(x).15f(x) = 4x3 + 15x2 - 24x + 5 =(Factor c
Basile [38]

If x=-5 is a zero, then the first factor of the polynomial would be (x + 5 )

To find the other two factors we can divide the polynomial by the expression (x+5).

Using synthetic division, we have:

-5 I 4 15 -24 5 (Coefficients of the dividend)

I -20 25 -5 (Multiplying each coefficient by the results of the substraction and adding)

-----------------------------------------------------------------------------------

4 -5 1 0 (Coefficients of the quotient)

The result of the division is 4x^2 - 5x + 1. Factoring it, we have:

4x^2 - 4x -x + 1 (Separating -5x into -x and -4x)

4x (x - 1) - (x -1) (Factoring each pair of terms)

(x-1)(4x-1) (Factoring using the common factor)

So the answer would be:

(x + 5 )(x-1)(4x-1)

3 0
8 months ago
4) Given the line with equation 2x + 5y= 10 :
Svetlanka [38]
A. <span>2x + 5y= 10
    5y= -2x+10
</span>-> y= -2/5x+2

b. The slope is 2

c. For the y  intecpet, x is always 0

y= -2/5x+2
y= -2/5(0)+2
y=0+2
y=2

(0,2) is the y-interecpt

d. Please veiw below

4 0
3 years ago
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