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velikii [3]
3 years ago
10

What is the range of the following function: f(x)=-x^2+x^-1 if the domain is {-2, -1, 1}

Mathematics
1 answer:
postnew [5]3 years ago
8 0

f(x)= -x^2 + x^-1

f(-2)= - (-2)^2 + (-2)^-1 = -4 - 1/2 = -9/2

f(-1)= - (-1)^2 + (-1)^-1 = -1 -1    =   -2

f(1) = - (1)^2 + (1)^-1 = -1 +1 = 0

The range is { -9/2, -2, 0}


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0.42 equals

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The simplest form for 0.42 is 21/50
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will the opposite of a number always,sometimes,or never be greater than the number itself??????? can someone do an example and a
weeeeeb [17]

When the number is positive, its opposite is less than the number.

9 ==> -9 . . . . . . less
72 ==> -72 . . . . less
324 ==> -324 . . less


When the number is negative, its opposite is greater than the number.

-8 ==> 8 . . . . . . greater
-3/4 ==> 3/4 . . . greater
-429 ==> 429 . . greater .

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8 0
3 years ago
Read 2 more answers
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
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