Answer:
Explanation:
using the formula p² + 2pq + 2pr + q²+ 2qr + r² = 1 where p is IA allele is 0.35 and q is IB allele is 0.15.
Thus, the expected frequency of people with type AB blood in this population will be (2pq) = 2 x 0.35 x 0.15 = 0.105
b. The expected frequency of people with type A blood will be p² + 2pr = where r is found using the formular p + q + r = 1 = 1 - (p+q) = 1 - (0.35+0.15) = 0.5
Thus, we have the expected frequency of people with type A blood to be (0.35² + 2x0.35x0.5) = 0.4725.
c. <u> p² + 2pr</u> + <u>2pq </u>+ <u>q² + 2qr</u> +<u> r²</u>
AA AO AB BB BO OO
1850 180 635 2335
frequency of IA- p = (1850 + 180/2) / 5000 = 0.388
frequency of IB- q = (635 + 180/2) / 5000 = 0.145
frequency of i- r = 2335/ 5000 = 0.467.
since r² = 2335, r = √2335 = 48.32
using the formula p + q + r = 1
The answer is binary fission
Answer:
The process of the formation of Urine starts when the blood enters the kidney and is filtered by the nephrons to separate the water from the larger elements that compound it like blood cells and proteins. Then, they go to the blood, and the elements that passed the filtration membrane go to the renal tubule to be moved to the bladder or be reabsorbed in case they are necessary for the body.
Explanation:
The Urine creation process starts with the blood entering the nephron in the kidneys. Then it is filtrated blocking blood cells and large proteins, making only water and smaller elements pass the filtration membrane. Then, cells and proteins, as well as the elements that couldn't pass the filtration membrane, go back to the bloodstream. While the elements that passed the filtration membrane go to the nephron to enter the renal tubule. In this tube some of the components that can still be used by the body are reabsorbed, the rest continues its journey to the bladder.
Sugar water ...............
