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Andreas93 [3]
4 years ago
7

HELP!! please explain how you got the answer too.

Mathematics
2 answers:
mixas84 [53]4 years ago
5 0

Answer:

H(0,-7) does lie on the graph of line y = 4.6x - 7

Step-by-step explanation:

All you have to do is simply plug in the x and y values.

From the point H (0,-7) we can say that

x = 0

y = -7

Now just plug it into the equation.

y = 4.6x - 7

(-7) = 4.6(0) - 7

-7 = -7

Since -7 does equal -7, the point H is on the line of y = 4.6x - 7.

nydimaria [60]4 years ago
4 0

Answer:

Point H does lie on the graph y = 4.6x - 7

Step-by-step explanation:

Step 1: Define

y = 4.6x - 7

H(0, -7)

Step 2: Substitute, Evaluate, and Check

-7 = 4.6(0) - 7

-7 = 0 - 7

-7 = -7

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Deffense [45]

The answers are 3 and -13

You need to plug 3 and -5 into x

By doing this, you get :

12 - 3^2       and

12 - (-5)^2

those expressions equal

12 - 9

12 - 25

So you get

3

-13

8 0
3 years ago
PLEASE PLEASE PLEASE HELP ME WITH THESE! Or I WILL FAIL!! PLEASE
Serga [27]
First ones 40 and I’m not sure bout the second one but through process of elimination either always or never cause nothing in math is uncertain or non existent
6 0
4 years ago
What is the value of root 12+root 12+root12....<br> ...............to infinite
Effectus [21]
X=root(12+root(12+root(...)))
x^2=12+root(12+root(12+root(...)))
x^2=12+x
x^2-x-12=0
(x+3)(x-4)=0
X=4
7 0
3 years ago
What percent of 200 miles is 150 miles
Anna71 [15]
150 miles is exactly 75% of 200 miles.
Hope that helped =)
4 0
3 years ago
I need help with questions #7 and #8 plz
katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

c^2 = a^2 + b^2 - 2ab \cos C

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

18^2 = 12^2 + 16^2 - 2(12)(16) \cos C

324 = 144 + 256 - 384 \cos C

-384 \cos C = -76

\cos C = 0.2

C = \cos^{-1} 0.2

C = 78.6^\circ

Now we use the law of sines to find angle A.

Law of Sines

\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

We know c and C. We can solve for a.

\dfrac{a}{\sin A} = \dfrac{c}{\sin C}

\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}

Cross multiply.

18 \sin A = 12 \sin 78.6^\circ

\sin A = \dfrac{12 \sin 78.6^\circ}{18}

\sin A = 0.6535

A = \sin^{-1} 0.6535

A = 40.8^\circ

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

a^2 = b^2 + c^2 - 2bc \cos A

b^2 = a^2 + c^2 - 2ac \cos B

c^2 = a^2 + b^2 - 2ab \cos C

Find angle A:

a^2 = b^2 + c^2 - 2bc \cos A

8^2 = 18^2 + 12^2 - 2(18)(12) \cos A

64 = 468 - 432 \cos A

\cos A = 0.9352

A = 20.7^\circ

Find angle B:

b^2 = a^2 + c^2 - 2ac \cos B

18^2 = 8^2 + 12^2 - 2(8)(12) \cos B

324 = 208 - 192 \cos A

\cos B = -0.6042

B = 127.2^\circ

Find angle C:

c^2 = a^2 + b^2 - 2ab \cos C

12^2 = 8^2 + 18^2 - 2(8)(18) \cos B

144 = 388 - 288 \cos A

\cos C = 0.8472

C = 32.1^\circ

8 0
3 years ago
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