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pentagon [3]
4 years ago
11

The width of a rectangle is 1/2 of its length. what are the sides of the rectangle if its perimeter in 63 in?

Mathematics
2 answers:
lesya [120]4 years ago
7 0
The length is: 42 inches
The width is : 21 inches
Bezzdna [24]4 years ago
7 0
This is the right ans...........

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Please help me, I’ll give brainliest
kolbaska11 [484]

Answer:

<em>x</em><em> </em><em>=</em><em> </em><em>4</em><em>5</em>

<em>y</em><em> </em><em>=</em><em> </em><em>5</em>

Step-by-step explanation:

<em>it</em><em> </em><em>is</em><em> </em><em>b</em><em>ecause</em>

<em>9</em><em>0</em><em>/</em><em>2</em><em> </em><em>=</em><em> </em><em>4</em><em>5</em>

<em>(</em><em>9</em><em>0</em><em>+</em><em>1</em><em>0</em><em>)</em><em>/</em><em>2</em><em>0</em><em> </em>

<em>(</em><em>1</em><em>0</em><em>0</em><em>)</em><em>/</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>,</em><em>5</em>

7 0
4 years ago
Can somebody help me with this question please
harina [27]

Answer:

34

Step-by-step explanation:

Points B,C,D, and E are points on the edge of the circle.

\angle BCD and \angle BED are in the same segment.

We have that: \angle BCD=34\degree

We want find m\angle BED

Recall that angles in the same segment are congruent.

\therefore \angle BED=\angle BCD=34

So the answer is 34

3 0
3 years ago
**For this question: you just have to come up w/ an equation.
QveST [7]
There's two actually.
0.25q + 0.10d = 3.85
q + d = 25
5 0
4 years ago
Can someone help me figure this out ?
asambeis [7]

Answer: AAS

Step-by-step explanation:

Lets call the intersection point between AC and DE F.

I think he meant the two triangles AFE and DFC.

We know angle A is congruent to angle D.

We also know AE is congruent to DC.

There is also a hidden piece of evidence which is AFE is congruent to DFC due to vertical angles.

We know two angles and 1 side, so we can use AAS to figure out that the two smaller triangles are congruent.

5 0
3 years ago
Please help
lys-0071 [83]
Part 1
1) The positive integers          ----------->  <span>D.) The natural numbers
</span>2.) An ordering of quantities  -----------> <span>B.) A sequence
</span>3.) 2, 4, 8, 16, . . ., 256            ----------->  <span>A.) An example of a finite sequence
</span>4.) 1, 3, 5, 7, . . .                        ----------->  <span>E.) An example of an infinite sequence
</span>5.) No first term is available   ----------->  C.) The reason the numbers . . . -4, -2, 0, 2, 4, . . . are not a sequence
Part 2
a_n=n^2+2\\ a_1=1+2=3\\ a_2=4+2=6\\ a_3=9+2=11\\ a_4=16+2=18\\ a_5=25+2=27
The answers is A.
Part 3
a_n=-1(\frac{1}{3})^{n-1} \\ a_1=-1(\frac{1}{3})^{1-1}=-1\\ a_2=-1(\frac{1}{3})^{2-1}=-\frac{1}{3}\\ a_3=-1(\frac{1}{3})^{3-1}=--\frac{1}{9}\\ a_4=-1(\frac{1}{3})^{4-1}=--\frac{1}{27}\\ a_5=-1(\frac{1}{3})^{5-1}=--\frac{1}{81}\\
The answers is B.
Part 4
The pattern in this sequence is:
a_n=2a^nb^{n-1}
Let's list first six terms:
a_n=2a^nb^{n-1}\\&#10;a_1=2a^1b^0=2a\\&#10;a_2=2a^2b^1=2a^2b\\&#10;a_3=2a^3b^2\\&#10;a_4=2a^4b^3\\&#10;a_5=2a^5b^4\\&#10;a_6=2a^6b^5\\
This is a infinite sequence. The patern is obvious and we could find any term within the sequence.


5 0
3 years ago
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