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daser333 [38]
3 years ago
10

How do you write 0.326 in word form?

Mathematics
1 answer:
ryzh [129]3 years ago
8 0
Three hundred twenty-six thousandths.
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lee and maya are collecting leaves for an art project. lee collects 24-100 of the total leaves needed. maya collects 4-10 of the
tiny-mole [99]

Answer:

16/25

Step-by-step explanation:

4/10=40/100

24/100=24/100

40+24=64

64/100

16/25

6 0
2 years ago
I need help solving this practice math problem ​
koban [17]
I think it’s D but I’m srry if u get it wrong
6 0
2 years ago
We need a rock garden with a perimeter of 12 feet and an area of 8 square feet what is the length and width
Katarina [22]

The dimensions of the rectangle can be a length of 2ft and a width of 4ft.

<h3>How to find the dimensions of the garden?</h3>

Remember that for a rectangle of length L and width W, the perimeter is:

P = 2*(L + W)

And the area is:

A = L*W

In this case, we know that the area is 8 square feet and the perimeter is 12 ft, then we have a system of equations:

12ft = 2*(L + W)

8ft² = L*W

To solve this, we first need to isolate one of the variables in one of the equations, I will isolate L on the first one:

12ft/2 = L + W

6ft - W = L

Now we can replace that in the other equation to get:

8ft² = (6ft - W)*W

This is a quadratic equation:

-W^2 + 6ft*W - 8ft² = 0

The solutions are given by Bhaskara's formula:

W = \frac{-6 \pm \sqrt{(6ft)^2 - 4*(-1)*(-8)} }{2*-1} \\\\W = \frac{-6 \pm 2}{-2}

Then we have two solutions:

W = (-6 - 2)/-2 = 4ft

W = (-6 + 2)/-2 = 2ft

If we take any of these solutions, the length will be equal to the other solution.

So the dimensions of the rectangle can be a length of 2ft and a width of 4ft.

if you want to learn more about rectangles:

brainly.com/question/17297081

#SPJ1

4 0
2 years ago
Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).
AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare.  If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3

\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1

Hence segments JL and MK are perpendicular

4 0
1 year ago
PLease help
Nina [5.8K]

Answer:

Range: 13 and 15        Mean: 247 and 286

Step-by-step explanation:

3 0
3 years ago
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