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Mrrafil [7]
3 years ago
9

(05.01)Elliot has been running a lawn care business since 2000. He cuts grass, trims, and weed whacks yards for his customers th

roughout the season. Each year, he has increased his fee by the same amount. The table shows what Elliot charged each customer for two given years of his business: Year Lawn Care Fee 2000 $750 2010 $1350 A. What is the rate of change and initial value for Elliot’s business? How do you know? B. Write an equation in slope-intercept form to represent the fees that Elliot charges each year.
Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0
Rate of change = (1350 - 750)/(2010 - 2000) = 600/10 = $60
Initial value = $750
Equation is y = 60x + 750; where y is the amount charged to customer and x is the number of years from 2000.
kodGreya [7K]3 years ago
6 0

Answer:

Rate of change: 60

Initial value: $750

You divided the rate of change and lawn care fees by number of years.  

y=60x+750.

I know this is SUPER late but i want to post this here to help anyone else out who may need help! :) XD



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aalyn [17]

Answer:

y=20x+14, where:

y is the total amount you would pay for using the sailboat

x is the number of hours the sailboat is used

Step-by-step explanation:

An equation in slope-intercept form is set up as y=mx+b. From the information provided, the equation would indicate that the cost of renting the boat would be equal to the price per hour for the number of hours plus the cost of lifejackets and the equation in slope-intercept form that can be used is:

y=20x+14, where:

y is the total amount you would pay for using the sailboat

x is the number of hours the sailboat is used

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3 years ago
Suppose an airline policy states that all baggage must be box shaped with a sum of​ length, width, and height not exceeding 114
NISA [10]

Answer:

Step-by-step explanation:

Represent the length of one side of the base be s and the height by h.  Then the volume of the box is V = s^2*h; this is to be maximized.

The constraints are as follows:  2s + h = 114 in.  Solving for h, we get 114 - 2s = h.

Substituting 114 - 2s for h in the volume formula, we obtain:

V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)

This is to be maximized.  To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:

dV

----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2

ds

Simplifying this, we get dV/ds = -4s^2 + 114s = 0.  Then either s = 28.5 or s = 0.

Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in

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7 0
3 years ago
Please help me ASAP
stellarik [79]

Answer:

<em>The Graph is shown below</em>

Step-by-step explanation:

<u>The Graph of a Function</u>

Given the function:

\displaystyle y=g(x)=-\frac{3}{2}(x-2)^2

It's required to plot the graph of g(x). Let's give x some values:

x={-2,0,2,4,6}

And calculate the values of y:

\displaystyle y=g(-2)=-\frac{3}{2}(-2-2)^2=-\frac{3}{2}(-4)^2==-\frac{3}{2}*16=-24

Point (-2,-24)

\displaystyle y=g(0)=-\frac{3}{2}(0-2)^2=-\frac{3}{2}(-2)^2=-\frac{3}{2}*4=-6

Point (0,-6)

\displaystyle y=g(2)=-\frac{3}{2}(2-2)^2=-\frac{3}{2}(0)^2=0

Point (2,0)

\displaystyle y=g(4)=-\frac{3}{2}(4-2)^2=-\frac{3}{2}(2)^2=-\frac{3}{2}*4=-6

Point (4,-6)

\displaystyle y=g(6)=-\frac{3}{2}(6-2)^2=-\frac{3}{2}(4)^2=-\frac{3}{2}*16=-24

Point (6,-24)

The graph is shown in the image below

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2 years ago
Mr Burns wants to buy every student in year 11 a doughnut
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26*5 is 130

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6 0
3 years ago
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bezimeni [28]

Answer:

Step-by-step explanation:

According to the first expression:

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According to the second expression:

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k: is the amount of money which is lost

2k:s hows the twice of amount which is lost

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