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Mrrafil [7]
3 years ago
9

(05.01)Elliot has been running a lawn care business since 2000. He cuts grass, trims, and weed whacks yards for his customers th

roughout the season. Each year, he has increased his fee by the same amount. The table shows what Elliot charged each customer for two given years of his business: Year Lawn Care Fee 2000 $750 2010 $1350 A. What is the rate of change and initial value for Elliot’s business? How do you know? B. Write an equation in slope-intercept form to represent the fees that Elliot charges each year.
Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0
Rate of change = (1350 - 750)/(2010 - 2000) = 600/10 = $60
Initial value = $750
Equation is y = 60x + 750; where y is the amount charged to customer and x is the number of years from 2000.
kodGreya [7K]3 years ago
6 0

Answer:

Rate of change: 60

Initial value: $750

You divided the rate of change and lawn care fees by number of years.  

y=60x+750.

I know this is SUPER late but i want to post this here to help anyone else out who may need help! :) XD



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