2.4 because 4.8/2 is 2.4. 14.4/4 is also 2.4. Constant of variation is the unit rate
Answer:
the answer is 4/5. The decimal does not repeat
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
56.5 inches
Step-by-step explanation:
You want to find the perimeter (or the length around the rectangle) to find much lace he needs. the formula for perimeter is 2L+2W=P. L being length, w being width and p being perimeter. Plug in the values for the equation and get 2(12.75)+2(15.5)=P. Multiply and get 25.5+31=56.5.
The median is 12.
There are 23 dots.
11 on 1 side. 12. 11 on the other
11+11+1=23.
