HELP DUE TOMORROW! 6TH GRADE MATH!

Please solve this question

Mandarinka [93]

Answer:

46?

Step-by-step explanation:

23*2=46

3 0

2 years ago

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Write the multiplicative inverse of <br>a) -13/19

irga5000 [103]

Answer:

$- \frac{19}{13}$

Step-by-step explanation:

$the \: multiplicative \: inverse \: of \: \\ - \frac{13}{19} = - \frac{19}{13}$

Product of a number and its multiplicative inverse should be equal to 1.

So,

$\bigg ( - \frac{13}{19} \bigg) \bigg ( - \frac{19}{13} \bigg)$

$= \frac{13}{19}\times \frac{19}{13}$

$=1$

3 0

3 years ago

A drawer contains loose socks. There are 2 blue and 4 black socks in the drawers. What is the probability that you choose a sock

stepladder [879]

The probability is p = 2/5, the correct option is the third one.

<h3>How to find the probability?</h3>

There is a total of 6 socks, such that 4 are black and 2 are blue.

Then the probability of first getting a black sock is the quotient between the number of black socks and the number of blue socks, which gives:

P = 4/6

Now there are 5 socks in total, such that 3 are black and 2 blue.

Then the probability of getting another black one is:

Q = 3/5

The joint probability (getting the two black socks) is given by the product of the individual probabilities:

p = (4/6)*(3/5) = 2/5

The correct option is the third one.

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

4 0

2 years ago

A maker of a certain brand of low-fat cereal barsclaims that the average saturated fat content is 0.5gram. In a random sample of

finlep [7]

Answer:

$t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386$

$p_v =2*P(t_{(7)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance. So then the claim makes sense

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=0.475$

The sample deviation calculated $s=0.183$

We need to conduct a hypothesis in order to check if the true mean is 0.5 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 0.5$

Alternative hypothesis: $\mu \neq 0.5$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=8-1=7$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(7)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance. So then the claim makes sense

4 0

3 years ago

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Choose the best decimal to represent 3 5/9

Ber [7]

Step 1: divide numerator (5) by the denominator (9): 5 ÷ 9 = 0.5555555555555556

Step 2: add this value to the the integer part: 3 + 0.5555555555555556 = 3.5555555555555554. So,

3 5/9 = 3.5555555555555554

3 0

3 years ago

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