The z-score corresponding to the actual mean of x = 15.2 can be calculated using the formula: z = (x - mean) / (SD / sqrt(n) ), where n is the sample size.
z = (15.2 - 15) / (1.8/sqrt(87)) = 1.04
Based on a z-table, the probability that z > 1.04 (and thus, the probability that x > 15.2) is 0.1492. This corresponds to a significance value of 1 - 0.1492 = 0.8508. Therefore, if alpha > 0.8508 (for example, 90%, 95%, or 99% confidence interval), then we fail to reject the null hypothesis, and assume that there is no significant difference from the mean.
I've posted my answer together with the image I think this problem required.
Answer:
it's the first I think but at least I tried
Answer: Their total budget last year was $40,000.
Step-by-step explanation:
Given : The Smiths spend 6% of their budget on entertainment.
i.e. , The money they spend on entertainment = 0.06 x ( Total budget)
{ 6% is converted to 0.06 , when we divide it by 100 to remove percentage)
Since , this year they plan to spend $2,580 on entertainment.
i.e. 0.06 x ( Total budget ) = $2,580
On dividing both sides by 0.06 , we get
( Total budget ) = $2,580 ÷ 0.06
= $43,000
Thus , their total budget for this year = $43,000
Also, Their total budget this year is $3,000 more than last year.
Therefore , their last year total budget = ( Total budget this year ) - $3000
= $43,000 - $3000
= $40,000
Hence, their total budget last year was $40,000.
Hope this helps! Also can I have brainliest? It’s ok if no :) have a nice day.
The answer should be 500.