Answer:
The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.
y = a(x-h)2 + k standard form
y = 5x2 - 4 original equation
y = 5(x-0)2 - 4 re-written in standard form
h = 0 k = -4
Four (4) units up is k + 4--->-4 + 4 = 0.
Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.
Step-by-step explanation:
hope this helps
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The answer to the question you are looking for is right in front of u
Answer:
D. (x - 2)(x - 2)
Step-by-step explanation:
x2 - 4x + 4 = x² - 2x - 2x +4
= x(x-2) - 2(x - 2)
= (x-2)(x-2)
HINT: - 2x +4 = -2 * x + (-2) * (-2) = -2 ( x -2)
Jus look and the answer above
Answer:
y= - 1/6x -1
Step-by-step explanation:
Given:
Perpendicular line has slope of reciprocal opposite to the given: - 1/6, so the equation:
Finding b using the intersected point:
- -2= -1/6*6 +b
- b= -2 +1= -1
So the equation is: