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3 years ago

The density of copper is 9.86g\cm³ work out the solid copper cuboid in kg

Mathematics

1 answer:

EleoNora [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Density of copper = 9.86 g / cm^3 = 9860 kg / m^3

= 9.86 x 1 / 1000 kg / cm^3 = 9.86 / 1000 Kg / cm^3

= 0.00986 kg / cm^3

= 9.86 x 1 / 1000 kg (1 / 100 m)^3

= 9.86 x 1000000 / 1000 kg / cm^3

Mass "m" = 9860 kg / m^3

thus the mass of copper in solid form is m = 9860 kg / m^3

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Mr. Mole left his burrow and started digging his way down at a constant rate. Time (minutes) Altitude (meters) 666 -20.4−20.4min

Juli2301 [7.4K]

Answer:

$-6$ meters.

Step-by-step explanation:

We have been given Mr. Mole left his burrow and started digging his way down at a constant rate.

We are also given a table of data as:

Time (minutes) Altitude (meters)

6 -20.4

9 -27.6

12 -34.8

First of all, we will find Mr. Mole's digging rate using slope formula and given information as:

$m=\frac{y_2-y_1}{x_2-x_1}$ , where,

$y_2-y_1$ represents difference of two y-coordinates,

$x_2-x_1$ represents difference of two corresponding x-coordinates of y-coordinates.

Let $(6,-20.4)$ be $(x_1,y_1)$ and $(9,-27.6)$ be $(x_2,y_2)$ .

$m=\frac{-27.6-(-20.4)}{9-6}$

$m=\frac{-27.6+20.4}{3}$

$m=\frac{-7.2}{3}$

$m=-2.4$

Now, we will use slope-intercept form of equation to find altitude of Mr. Mole's burrow.

$y=mx+b$ , where,

m = Slope,

b = The initial value or the y-intercept.

Upon substituting $m=-2.4$ and coordinates of point $(6,-20.4)$ , we will get:

$-20.4=-2.4(6)+b$

$-20.4=-14.4+b$

$-20.4+14.4=-14.4+14.4+b$

$-6=b$

Since in our given case y-intercept represents the altitude of Mr. Mole's burrow, therefore, the altitude of Mr. Mole's burrow is $-6$ meters.

6 0

3 years ago

Read 2 more answers

Javier designs leather shoes at his workshop. He charges $45 for women's shoes and $50 for men's shoes. He needs to make $2,500

AVprozaik [17]

X = womens, y = mens

45x + 50y = 2500....if there is no women, then x = 0
45(0) + 50y = 2500
50y = 2500
y = 2500/50
y = 50.....there would be 50 male customers to meet his expenses

5 0

3 years ago

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Caren wants to record the change in temperature during the day.

Fiesta28 [93]

Not circle for sure. Line graph is for plotting not really demonstrating a change. Picto graph is just like line plotting. Probably the bar graph works the best to see the smoothness and flow of how it increases and decreases.

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3 years ago

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A fair coin is to be tossed 20 times. Find the probability that 10 of the tosses will fall heads and 10 will fall tails, (a) usi

lbvjy [14]

Using the distributions, it is found that there is a:

a) 0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

b) 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

c) 0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item a:

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

20 tosses, hence $n = 20$ .
Fair coin, hence $p = 0.5$ .

The probability is P(X = 10), thus:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.5)^{10}.(0.5)^{10} = 0.1762$

0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item b:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

The probability of an exact value is 0, hence 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item c:

For the approximation, the mean and the standard deviation are:

$\mu = np = 20(0.5) = 10$

$\sigma = \sqrt{np(1 - p)} = \sqrt{20(0.5)(0.5)} = \sqrt{5}$

Using continuity correction, this probability is $P(10 - 0.5 \leq X \leq 10 + 0.5) = P(9.5 \leq X \leq 10.5)$ , which is the p-value of Z when X = 10.5 subtracted by the p-value of Z when X = 9.5.