Answer:
Step-by-step explanation:
1). ∠7 ≅ ∠ 2 (alternate exterior)
m∠7 = m∠2 = 30°
2). ∠4 and ∠1 are supplementary angles
m∠1 = 180° - 72° = 108°
Round pan volume is:
3.14•r^2•h
D=7 so r=3.5 in
3.14• (3.5^2)•2 = 76.97 in^3
Rec. pan vol. is :
9•6•2= 108 in^3
Rec. Pan is larger because 108 in^3 is > 76.97 in^3 :) .
The icing that will be needed to frost the round cake pan is:
We need to find the surface area:
S.A= 3.14r^2 + 2 • 3.14•r • h .... 3.14 is the value of PI
So, S.A= 3.14• 3.5^2 + 6.28• 3.5• 2= 82.47 in^2 the icing that'll be needed to frost the round cake pan.
Icing that will be needed for the rec. cake pan is:
2•9•2=36 in^2
6•9•2= 108in^2
6•2= 12 in^2
S.A= 156 in^2 the icing needed to frost the rec. cake pan .... the S.A of all sides except the bottom one :).
Good luck ;-)
Equal ratios are those that are equal to each other.
Example:-
4/2 = 8/4
Also, ratios compare to values, and there are 3 ways to write a ratio.
4/2 and 4:2 and 4 to 2
Answer:
c
Step-by-step explanation:
volume of cylinder = πr^2h
r = 6.5
h = 13+13+13 = 39
cylinder volume = 1647.75π cm^3
volume of one sphere = 4/3 π r^3
= 366.16π cm^3
space not occupied by tennis balls = 1647.75π-3(366.16π)=549.25π cm^3
