All categories

2 years ago

Finn looked at 4 websites every 16 hours. At that rate, how many would he look at in 8 hours?

2 answers:

7 0

Well the answer to this question is 2 websites.
Here is how to solve it:
16:4 = 8:x
= 16/2: 4/2
= 8 hours : 2 websites.
Also, I just want to say happy new year to you and also have a fantastic day!
Also, can you please mark my answer as the brainliest answer?
Thanks.

Leviafan [203]2 years ago

3 0

Answer:

2 Websites

Step-by-step explanation:

16 divided by 2 is 8. 8 hours means 2 websites

You might be interested in

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago

Olution set for 8( 3x - 2)2(7x + 12)?

In-s [12.5K]

Answer: x ≤ 4
___________

6 0

3 years ago

Select all equations that have graphs with the same y-intercept.

Firdavs [7]

Y=3x-8,5x-8,2x-8,1/3x-8 how to find it is to look at the (x,y) if the equation have the same y (y-intercept)

8 0

2 years ago

To earn an A in an algebra course, a student must have a test average of at least 90. Mary has grades of 95, 82, 88 on her first

Fofino [41]

Answer: Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

Step-by-step explanation:

Let x be the grades scored by Mary in the fourth algebra test.

Mary has grades of 95, 82, 88 on her first three algebra tests.

Then, the combined scores in four test will become = 95+82+88+x = 265+x

Average score = (Sum of all scores) ÷ (Number of tests)

$=\dfrac{265+x}{4}$

As per given ,

To earn an A in an algebra course, a student must have a test average of at least 90.

i.e. Average score ≥ 90

$\Rightarrow\ \dfrac{265+x}{4}\geq90\\\\\Rightarrow\ 265+x\geq 90\times4=360\\\\\Rightarrow\ x\geq360-265 =95\\\\\Rightarrow\ x\geq90$

Hence, Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

5 0

2 years ago

List these numbers from least to greatest:<br><br> -1 2/5, 0, -2.3, 3/4, and<br> -1 9/10

kap26 [50]

Answer:

-2.3, -1 9/10, -1 2/5, 0, 3/4.

Step-by-step explanation:

First thing we need to do is express all of the fractions and the decimal in the same unit.

Let's turn the decimal into a fraction.

-2.3 = -2 3/10. The 3 is in the tenths place, so that means 3 over 10 or 3/10. The 2 is in the ones place so we get the 2 as a whole number.

Okay, now we need to express the fractions with the same denominator. You MUST do this if you are going to compare fractions.

First,

let's turn all the mixed numbers into improper fractions.

-1 2/5 = -7/5

-2 3/10 = -23/10

-1 9/10 = -19/10.

The last 2 already have the same denominator of 10, so we'll just change the -7/5 to have a denominator of 10. 5 x 2 equals 10, so we MUST also multiply by the numerator by 2. Whatever is done to the denominator has to be done to the numerator as well.

5 x 2 = 10

7 x 2 = 14.

Now, here is what we have.

-14/10, 0, -23/10, 3/4, -19/10.

First, know that negative numbers are ALWAYS SMALLER than zero and ANY positive number.

And, with negative numbers, the number that looks "greater" is actually lesser. For example, -5 is greater than -3 because -3 is closer to 0.

So, let's compare the negative fractions.

-14/10, -23/10, -19/10.

Ignoring the (-) the one that *looks* greatest is 23 because it has the greatest number in the numerator, however, because this is negative numbers, it's actually the smallest.

Second "biggest" is -19/10 but again, this is negatives, so its actually second smallest.

The only number now is -14/10 so that's the next smallest.

0 is obviously less than 3/4 so 0 comes next. And lastly, 3/4 is the only number we have left! so, 3/4 is the greatest!

LEAST TO GREATEST:

-2.3, -1 9/10, -1 2/5, 0, 3/4.

6 0

3 years ago

Finn looked at 4 websites every 16 hours. At that rate, how many would he look at in 8 hours?​

Finn looked at 4 websites every 16 hours. At that rate, how many would he look at in 8 hours?