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Novay_Z [31]
3 years ago
5

Ni Hua is an adventurous traveler. He skydives twice in every island he visits and skydives thrice in every peninsula he visits.

In the last decade, Ni Hua went skydiving a total of 454545 times in the 191919 islands and peninsulas that he visited. How many islands and peninsulas did Ni Hua visit?
Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

Answer: He visited 12 island and 7 peninsulas.

Step-by-step explanation:

Let x be the number of island he visited and y be the number of peninsulas he visited,

Since, He visited 19 islands and peninsulas,

⇒ x + y = 19, ------(1)

Also, He went skydiving a total of 45 times in which he skydived twice in every island and skydived thrice in every peninsula,

⇒ 2x + 3y = 45 ------(2),

Equation (2) - 2 × Equation (1),

We get,

y = 45 - 38 = 7

By substituting this value in equation (1),

We get, x = 12

Hence, He visited 12 island and 7 peninsulas.

solniwko [45]3 years ago
3 0
Let x and y be islands and peninsulas respectively
x+y=191919
2x+3y=454545

y = 191919- x

2x + 3 (191919 - x) = 454545
2x + 575757 - 3x = 454545
2x-3x = 454545 - 575757
-x = -121212
x = 121212

121212 + y = 191919
y = 191919 - 121212
y = 70707

Ni Hua visited 121212 islands and 70707 peninsulas
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Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (
Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

(c) 209 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138    (1)

The second equation in the unknowns is

3B + 5N = 71  (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===>   40B + 30N = 690   (3)

Multiplying (2) by 6 ===>  18B + 30N = 426    (4)

(3) - (4) eliminates the N variables and yields

22B = 264   ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==>  36 + 5N = 71 ==> 5N = 71-36 = 35 ==>  N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

(c) If we add both equations (1) and (2), we get

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0
1 year ago
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