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Rom4ik [11]
3 years ago
6

Solve each system of equations by substitution Y=4x+13 y=6x+19

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0

Answer:

I believe the answer to this question is: (-3,1) X=-3, Y=1.

You might be interested in
The ratio of art class to music class is 4:3. If there is 8 more students in art class, how many students are in music class
pishuonlain [190]

Answer:

9 students in music class.

Step-by-step explanation:

In art there are 4 and since there are 8 more 8 + 4 = 12. so there are 12 in Art.

4 x _ = 12. —> 4 x 3 = 12.
so we need to do the same for music class.

For music there are 3.
so we multiply by 3 like we did with the 4.

3 x 3 = _ —> 3 x 3 =9.
so there are 9 students in music class.


6 0
2 years ago
The cost of a car rental is thirty dollars a day plus fifteen cents a mile. If the total cost to rent the car was one hundred an
Elan Coil [88]

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose car was driven x miles in its 4 days trip.

Cost of a car rental is thirty dollar per day.

So, for 4 days, the car rental will be = 30*4=120 $

For 1 mile, it adds fifteen cents,

So, for x miles, the cost will be = 0.15 x $

As per question, total rent is 180 $

Total rent will be = 120 + 0.15 x = 180

Subtracting 120 in both sides

0.15 x = 180-120=60

x=\frac{60}{0.15}

x=400

It means car was driven 400 miles.   :   Answer

Hope it will help :)

4 0
3 years ago
Which equation represents a line which is perpendicular to the line y = -x + 8?
natima [27]

Two lines are perpendicular between each other if their slopes fulfills the following property

m_1m_2=-1

where m1 and m2 represents the slopes of line 1 an 2, respectively.

To find the slope of a line we can write it in the form slope-intercept form

y=mx+b

Our original line is

y=-\frac{1}{8}x+8

Then its slope is

m_1=-\frac{1}{8}

Now we have to find the slope of the second line. Using the first property,

\begin{gathered} m_1m_2=-1_{} \\ -\frac{1}{8}m_2=-1_{} \\ m_2=(-1)(-8) \\ m_2=8 \end{gathered}

Then the second line has to have a slope of 8.

The options given to us are:

\begin{gathered} x+8y=8 \\ x-8y=-56 \\ 8x+y=5 \\ y-8x=4 \end{gathered}

Then we have to determine which of these options have a slope of 8. To do that we write them in the slope-intercept form:

\begin{gathered} x+8y=8\rightarrow y=-\frac{1}{8}x+1 \\ x-8y=-56\rightarrow y=\frac{1}{8}x+7 \\ 8x+y=5\rightarrow y=-8x+5 \\ y-8x=4\rightarrow y=8x+4 \end{gathered}

Once we have the options in the right form, we note that the only one of them that has a slope of 8 is the last one.

Then the line perpendicular to the original one is

y-8x=4

8 0
1 year ago
Identify the correct algebraic expression for the following scenario:
7nadin3 [17]
H x 5=h5
h5/8
I think it’s this it also may be
(h x 5)/8
6 0
3 years ago
Read 2 more answers
What is tan theta when csc theta =2 sqrt 3?
Slav-nsk [51]

Answer:

\displaystyle \tan\theta=\frac{\sqrt{11}}{11}

Step-by-step explanation:

<u>Trigonometric Identities</u>

If the trigonometric function value of an angle is given, we can find the rest of the trigonometric values of the angle by using one or more of the fundamental identities.

To solve this problem, we need to use the following identities:

\displaystyle \cot^2\theta=\csc^2\theta-1

\displaystyle \tan\theta=\frac{1}{\cot\theta}

Since we are given:

\displaystyle \csc\theta=2\sqrt{3}

And the angle is in the first quadrant, calculate the cotangent:

\displaystyle \cot^2\theta=(2\sqrt{3})^2-1

\displaystyle \cot^2\theta=4*3-1=11

\displaystyle \cot\theta=\sqrt{11}

The tangent is:

\displaystyle \tan\theta=\frac{1}{\sqrt{11}}

Rationalizing the denominator:

\displaystyle \tan\theta=\frac{1}{\sqrt{11}}*\frac{\sqrt{11}}{\sqrt{11}}

\boxed{\displaystyle \tan\theta=\frac{\sqrt{11}}{11}}

7 0
3 years ago
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