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Ostrovityanka [42]
3 years ago
5

When placed end to end, three red rods are 2 cm longer than than 2 blue rods. Three blue rods are 2 cm longer than four red rods

. How long is each rod?
Mathematics
1 answer:
Oxana [17]3 years ago
5 0

Answer:

Red = 10 cm, blue = 14 cm

Step-by-step explanation:

<em>Let the length of each red rod be </em><em>r </em><em>and each blue rod be </em><em>b</em>

<u>Then we have:</u>

  • 3r - 2b = 2
  • 3b - 4r = 2

<u>Multiply the first equation by 3 and the second one by 2:</u>

  • 9r - 6b = 6
  • 6b - 8r = 4

<u>Add the equations to eliminate one of variables:</u>

  • 9r - 8r = 6 + 4
  • r = 10 cm

<u>Find the value of b:</u>

  • 3*10 -2b = 2
  • 30 - 2 = 2b
  • 2b = 28
  • b = 14 cm

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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
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Answer:

(a)Revenue function, R(x)=580x-x^2

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit,P(x)=-35x^2+280x-900

(d)x=4

Step-by-step explanation:

<u>Part A </u>

Price Function= 580 - 10x

The revenue function

R(x)=x\cdot (580-10x)\\R(x)=580x-x^2

The marginal revenue function

\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x

<u>Part B </u>

<u>(Fixed Cost)</u>

The total cost function of the company is given by c=(30+5x)^2

We expand the expression

(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2

Therefore, the fixed cost is 900 .

<u> Marginal Cost Function</u>

If  c=900+300x+25x^2

Marginal Cost Function, \frac{dc}{dx}= (900+300x+25x^2)'=300+50x

<u>Part C </u>

<u>Profit Function </u>

Profit=Revenue -Total cost

580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900

<u> Part D </u>

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4

The number of cakes that maximizes profit is 4.

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