We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA=
. Hence CM=GC+GM=3*
. Now, since GM is normal to AB, we have by the pythagoeran theorem that:
Hence, we calculate from this that AC^2= 28, hence AC=2*
=BC. Thus, the perimeter of the triangle is 2+4*
.
X would be equal to time and y be equal to distance
The y axis would be measuring distance and the x axis would be measuring time. Another name for a speed graph is the distance time graph. The y axis would be measuring the distance covered by the truck in meters and the x axis would be for the time it takes to reach that distance in second.
B) 2-6 would represent contact motion, meaning the vehicle is at rest. The time would be increasing from 2-6 to however the distance remains the same which is 20m
El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>
En esta pregunta debemos encontrar el volumen <em>remanente</em> entre el espacio de una caja <em>cúbica</em> y una esfera introducida en el elemento anterior. El volumen <em>remanente</em> es igual a sustraer el volumen de la pelota del volumen de la caja.
Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:
Cubo
V = l³
V = (4 cm)³
V = 64 cm³
Esfera
V' = (4π / 3) · R³
V' = (4π / 3) · (2 cm)³
V' ≈ 33.5103 cm³
Segundo, determinamos la diferencia de volumen entre los dos elementos:
V'' = V - V'
V'' = 64 cm³ - 33.5103 cm³
V'' = 30.4897 cm³
El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
Para aprender más sobre volúmenes: brainly.com/question/23940577
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On the map ,
1cm=5km
therefore , 4.7cm= 5/1 x 4.7
=23.5 km <--------------answer
