When 2 secants intersect a circle:
(DC + CE) * CE = (AB + BE) * BE
( 1 + (x+4)) * (x+4) = (11 + (x+1)) * (x+1)
x + x^2 + 4x + 4 +4x +16 = 11x +x^2 +x +11 +x +1
9x + 20 = 13x + 12
4x = 8
x = 2
Source:
http://www.1728.org/circangl.htm
Scroll down to Two Intersecting Secants
Gee - that was a little bit of work!!
Answer: 4n-7
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
9 + 3 = 12
Where are these "hearts"?
Area of triangle = (1/2)*b*h = (1/2)*7*10
= 7*5 = 35 squared cm
<span>The equation x^2 - 36 = 5x is a quadratic equation and can be solved thus:
x^2 - 36 = 5x
x^2 - 5x - 36 = 0
x^2 + 4x - 9x - 36 = 0
x(x + 4) - 9(x + 4) = 0
(x - 9)(x + 4) = 0
x - 9 = 0 or x + 4 = 0
x = 9 or x = -4
Therefore, the positive solution of x^2 - 36 = 5x? is 9.</span>
