Answer:

Step-by-step explanation:
Given that the 2 triangles are congruent based on the Hypotenuse-leg theorem, this implies that:
, and
Using the expression,
, solve for y:



Volume of an iceberg = 7685 cubic feet
Since, density of ice = 0.917 
We have to determine the mass of the ice.
Since density = 
Since the unit of density is in
, first we will convert the density unit in kilogram.
Since, 1 kilogram = 1000 gram
Therefore, density = 
= 0.000917 
Since, the density unit is in cubic centimeter. We will convert it into cubic feet.
1 cubic centimeter = 0.00003531466 cubic feet
Therefore, 0.000917
= 0.000917 x 0.00003531466
= 0.0000000323
.
Now, mass = 
= 0.0000000323
7685
= 0.000248
=0.00025
.
Therefore, the mass of ice is 0.00025
.
Answer:
B
Step-by-step explanation:
Make a proportion.
x is the number of balloons sold each day.

Answer:
$2.16 per pound
Step-by-step explanation:
First, you would need to divide the price by the amount
$12.96 / 6 lbs = $2.16 per pound
That is the unit price
Answer:
Check the explanation
Step-by-step explanation:
1) Algorithm for finding the new optimal flux: 1. Let E' be the edges eh E for which f(e)>O, and let G = (V,E). Find in Gi a path Pi from s to u and a path
, from v to t.
2) [Special case: If
, and
have some edge e in common, then Piu[(u,v)}uPx has a directed cycle containing (u,v). In this instance, the flow along this cycle can be reduced by a single unit without any need to change the size of the overall flow. Return the resulting flow.]
3) Reduce flow by one unit along 
4) Run Ford-Fulkerson with this sterling flow.
Justification and running time: Say the original flow has see F. Lees ignore the special case (4 After step (3) Of the elgorithuk we have a legal flaw that satisfies the new capacity constraint and has see F-1. Step (4). FOrd-Fueerson, then gives us the optimal flow under the new cePacie co mint. However. we know this flow is at most F, end thus Ford-Fulkerson runs for just one iteration. Since each of the steps is linear, the total running time is linear, that is, O(lVl + lEl).