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erma4kov [3.2K]
3 years ago
6

Five gerbils cost p dollars. How many dollars will it cost to buy 1 gerbil? How many dollars will it cost to buy g gerbils? How

many gerbils can you purchase for 1 dollar? How many gerbils can you purchase for d dollars?.
Mathematics
1 answer:
Fudgin [204]3 years ago
4 0
5 gerbils = p dollars
1 gerbil = p/5 dollars
g gerbils = pg / 5 dollars

5/p gerbils = 1 dollar
5d/p gerbils = d dollars
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The average hourly charge of plumbers in the Denver area is $84.00 with a standard deviation of $4.00. Assume that the hourly ch
Simora [160]

Answer:

The probability is 0.31

Step-by-step explanation:

In this question, we are tasked with calculating the probability that a random plumber called at Denver will charge an amount greater than $86 given the mean and the standard deviation.

Firstly, we calculate the standard score of $86 using the mean and the standard deviation.

Mathematically;

z-score = (x-mean)/SD

where x = 86, mean = 84 and SD = 4

z-score = (86-84)/4 = 2/4 = 0.5

Hence, we want to calculate P(z ≥ 0.5)

Using standard table

P( (z ≥ 0.5) = 1 - P(z ≤ 0.5) = 1 - ( 0.19146 + 0.5) = 0.30854

To the nearest hundredth = 0.31

5 0
3 years ago
Kevin is 6 years older than Timothy, and 4 years ago Kevin was twice as old as Timothy. Find their present ages.
vovangra [49]
<span>Kevin is 16
Timothy is 10
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check:
4 yrs ago Kevin was 12
4 yrs ago Timothy was 6
Kevin was twice his age
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6 0
3 years ago
An inlet pipe can fill an empty swimming pool in 7 hours, and another inlet pipe can fill a pool in 2 hours. How long will it ta
Naddika [18.5K]
To do this, you have to make it like this: 



4 0
3 years ago
Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b
77julia77 [94]

Answer:

The value is UCL  =  10.8  

Step-by-step explanation:

From the question we are told that

    The sample mean is  \= x  =  9 \  ounce

    The sample size is  n =  25

    The standard deviation is  \sigma =  3 \ ounce

Given that the sample size is not large enough i.e  n<  30  we will make use of the student t distribution table  

From the question we are told the confidence level is  99.7% , hence the level of significance is    

      \alpha = (100 -99.7 ) \%

=>   \alpha = 0.003

Generally the degree of freedom is  df =  n- 1

=>  df =  25 - 1

=>  df =  24  

Generally from the student t distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom of df =  24   is  

   t_{\frac{\alpha }{2} , 24 } = 3.0

Generally the margin of error is mathematically represented as  

      E = t_{\frac{\alpha }{2} , 24} *  \frac{\sigma }{\sqrt{n} }

=>     E = 3.0 *  \frac{3 }{\sqrt{25} }

=>     E =1.8

Gnerally the  upper control chart limit  for 99.7% confidence is mathematically represented as

         UCL  =  \= x  + E

=>      UCL  =  9 + 1.8  

=>      UCL  =  10.8  

     

4 0
2 years ago
Write an algebraic expression for julie runs three miles less than twice the number of miles,n that Hannah runs
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2n-3 I think that thats the answer
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