Answer:
The probability is 0.31
Step-by-step explanation:
In this question, we are tasked with calculating the probability that a random plumber called at Denver will charge an amount greater than $86 given the mean and the standard deviation.
Firstly, we calculate the standard score of $86 using the mean and the standard deviation.
Mathematically;
z-score = (x-mean)/SD
where x = 86, mean = 84 and SD = 4
z-score = (86-84)/4 = 2/4 = 0.5
Hence, we want to calculate P(z ≥ 0.5)
Using standard table
P( (z ≥ 0.5) = 1 - P(z ≤ 0.5) = 1 - ( 0.19146 + 0.5) = 0.30854
To the nearest hundredth = 0.31
<span>Kevin is 16
Timothy is 10
------------
check:
4 yrs ago Kevin was 12
4 yrs ago Timothy was 6
Kevin was twice his age
OK</span>
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The sample mean is 
The sample size is n = 25
The standard deviation is 
Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table
From the question we are told the confidence level is 99.7% , hence the level of significance is
=>
Generally the degree of freedom is 
=> 
=>
Generally from the student t distribution table the critical value of
at a degree of freedom of
is
Generally the margin of error is mathematically represented as
=>
=>
Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as

=>
=>