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3 years ago

Help please number 11.

Mathematics

2 answers:

BaLLatris [955]3 years ago

4 0

The answer is C. Your welcome

Alexxandr [17]3 years ago

3 0

I think the answer is probably C too

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Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean $\mu=510$ ,

Standard deviation $\sigma=100$

Sample mean $x=300$

Percentage of students scored below 300 is given by,

$P(Z\leq \frac{x-\mu}{\sigma})\times 100$

$=P(Z\leq \frac{300-510}{100})\times 100$

$=P(Z\leq \frac{-210}{100})\times 100$

$=P(Z\leq-2.1)\times 100$

$=0.0179\times 100$

$=1.79\%$

Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

$P(x\leq t)=0.90$

Now, $P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90$

$P(Z< \frac{t-\mu}{\sigma})=0.90$

$\frac{t-\mu}{\sigma}=1.28$

$\frac{t-510}{100}=1.28$

$t-510=128$

$t=128+510$

$t=638$

Score puts someone in the 90th percentile is 638.

5 0

3 years ago

I need help with this . I don’t get how

Svetradugi [14.3K]

Simply collect like terms, numbers and or variables that have the same number and type of variable.

For example 15x^2 and 10x^2 are like terms. Circle the sign in front of the term to perform the correct operation.

5 0

2 years ago

Uma pessoa deseja restaurar seu veículo antigo e para isso deverá contratar serviços mecânico, de funilaria e de autoelétrica. P

Leni [432]

Answer:

CI=P*(1 + R/100)^18

A=(CI + P) = P(1+R/100)^18

13500/P=1(100+R/100)^18

A/P=(100+R/100)^18

A=13500$ as (750 * 18)

(13500)/P=(1 +1.15/100)18

(13500)/P=(1+1.15/100)18

13500=((1.0115)^18

P=R$10989.02

Step-by-step explanation:

CI=Compound Interest

A=Amount

P=Principal.

3 0

2 years ago

Describe the motion of a particle with position (x, y) as t varies in the given interval. (For each answer, enter an ordered pai

DerKrebs [107]

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating $t$ in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity: