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DiKsa [7]
3 years ago
10

The drama club can wash 9 cars in 40 minutes.  At this rate, how many cars can they wash in 2 hours? Caution: turn hours to minu

tes!
Mathematics
1 answer:
Natali [406]3 years ago
6 0

Answer:

l am pretty sure the answer is 27

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For Home Economics class, Sandra has 5 cups of flour. She made 3 batches of cookies that each used 1.5 cups of flour. Write and
Lemur [1.5K]
Sandra has .5 of flour left after making 3 batches of cookies

6 0
2 years ago
8. Patrice and Don buy a home for $92,000. The property tax rate is$39.50 per $1,000 of assessed value. The assessment rate is 4
Kaylis [27]

We start by calculating the assessed value, that is 41% of the price.

The price is $92,000.

Then, the assessed value is:

AV=a\cdot P=\frac{41}{100}\cdot92000=0.41\cdot92000=37720

The property tax rate is $39.50 per $1000 of assessed value, so we can express this rate as:

\text{tax rate}=\frac{39.50}{1000}=0.0395

We then can multiply this rate by the assessed value to calculate the total property tax:

\text{tax}=0.0395\cdot37720=1489.94

NOTE: we could have also multiplied 39.50 by 37.72. The value 37.72 is the thousands of dollars of assessed value. We would have obtained the same result: 39.50*37.72=1489.94.

Answer: the property tax is $1,489.94.

3 0
1 year ago
What is the solution to the equation-3(h+5)+2 = 4(h+6)- 9?<br> h= 4<br> h= -2<br> h = 2<br> h = 4
ruslelena [56]
Expanding
-3h-15+2=4h+24-9
-3h-4h=24-9-2+15
-7h=28
h=4
8 0
2 years ago
PLEASE HELP ME I WILL GIVE YOU POINTS
Brilliant_brown [7]

Answer:I got 18.28

Step-by-step explanation:

so for getting the perimeter, you only need the outer line, so you sum the measurements you have for the rectangle: 1+2+2+7= 12. After that you need the circumference of the circle, you can figure it out by using the formula C = 2pi(r) You can find the radius by substracting the known sides of the rectangle attached to the circle from the bottom base and then dividing it in 2, leaving us with a radius of 2. Then we input values; C=2pi(2) which equals 4pi, but we need to divide that in half since it’s only half a circle. That leaves us with 2pi, or 6.28. Then we add the perimeter of the square, which was 12, and 6.28+12= 18.28

4 0
2 years ago
Evaluate the surface integral:S
rjkz [21]
Assuming S does not include the plane z=0, we can parameterize the region in spherical coordinates using

\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle

where 0\le u\le2\pi and 0\le v\le\dfrac\pi/2. We then have

x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v
(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v

Then the surface integral is equivalent to

\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du

We have

\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle
\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle
\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle
\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v

So the surface integral is equivalent to

\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du
=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv
=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw

where w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv.

=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}
=\dfrac{243}2\pi
4 0
3 years ago
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