Question

According to the general equation for conditional probability, if P(A and B^)= 1/6 and P(B')= 7/18, what is P(A and B') ?

Answer 1

The answer is 3/7 APEX

Answer 2

Answer:

The required probability is $P(A/B')=\frac{3}{7}$  

Step-by-step explanation:

Given : $\text{P(A and }B')=\frac{1}{6}$ and $P(B')=\frac{7}{18}$  

To find : What is  P(A/B') ?

Solution :

The conditional probability states that,

$P(A/B)=\frac{PA\cap B}{P(B)}$

According to given situations,

The conditional probability is

$P(A/B')=\frac{P(A\cap B')}{P(B')}$

Substitute $P(A\cap B')=\frac{1}{6}$ and $P(B')=\frac{7}{18}$

$P(A/B')=\frac{\frac{1}{6}}{\frac{7}{18}}$

$P(A/B')=\frac{1\times 18}{6\times 7}$    

$P(A/B')=\frac{3}{7}$  

Therefore, The required probability is $P(A/B')=\frac{3}{7}$