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crimeas [40]
3 years ago
11

Is it possible to divide 0 by 27 ?

Mathematics
2 answers:
tekilochka [14]3 years ago
8 0
You cant divide by 0.
No matter what number your dividing by 0, the answer will always will be 0
Mumz [18]3 years ago
5 0

Answer:

No. Dividing by 0 is not rational, no number works.

You might be interested in
3 pineapples, 2 cabbages and 6 bananas cost a total of $27.
vesna_86 [32]
3p + 2c + 6b = 27
2p + 3c + 4b = 23
4p + 1c + 8b = 31
===============
take any 2 equations and eliminate a variable

3p + 2c + 6b = 27
4p + 1c + 8b = 31....multiply by -2
---------------------
3p + 2c + 6b = 27
-8p - 2c - 16b = - 62 (result of multiplying by -2)
--------------------add
-5p - 10b = - 35

Now take one equation, and the other equation that u have not used already, and eliminate the same variable.

4p + 1c + 8b = 31.....multiply by -3
2p + 3c + 4b = 23
---------------------
-12p - 3c - 24b = - 93 (result of multiplying by -3)
2p + 3c + 4b = 23
----------------------add
-10p - 20b = - 70

now take ur 2 equations that u eliminated the c in, and eliminate another variable

-5p - 10b = -35......multiply by -2
-10p - 20b = -70
---------------------
10p + 20b = 70 (result of multiplying by -2)
-10p - 20b = -70
-------------------add
0 = 0

when u get a result such as  0 = 0....this means there is infinite solutions to this problem

8 0
3 years ago
I Need Help With This, It is My Last question
alina1380 [7]
Answer : c
I believe this is correct
4 0
3 years ago
Read 2 more answers
Which of the following statements about photocopier A1 is correct compared to the other photocopiers?
Sati [7]

Answer:

Option 2

Step-by-step explanation:

Number of breakdowns of the photocopiers in year 2011,

A1 = 15

A2 = 21

B1 = 34

B2 = 32

B3 = 23

Option (1)

A1 had just under a half the number of breakdowns compared to photocopier B3.

Half of B3 = 12

And A1 = 15

Therefore, A1 > B3

So the statement is False.

Option (2)

A1 had just under 50% of the breakdowns compared to photocopier B2

50% of the breakdowns of B2 = 16

A1 = 15

So, A1 < 50% of B2

Statement (2) is True.

Option (3)

A1 had more than 25 extra breakdowns compared to B1.

A1= 15

B1 = 34

A1 < B1

Therefore, statement is False.

Option (4)

A1 had 6% less breakdowns than photocopier A2.

A1 = 15

A2 = 21

A2 - A1 = 21 - 15 = 6

Percentage less breakdowns = \frac{6}{21}\times 100 = 28.6%

So this Option is False.

Therefore, Option (2) is the correct option.

3 0
3 years ago
Determine the scale factor of the function f(x)=1/4x^2
S_A_V [24]
\bf \stackrel{\textit{parent function}}{f(x)=x^2}\qquad  \quad f(x)=\cfrac{1}{4}x^2\impliedby \frac{1}{4},\textit{ 4 times as wide as its parent}
7 0
3 years ago
What is the whole of 15% of <br><br> is 12.
Morgarella [4.7K]
The whole would be 72
4 0
4 years ago
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