3p + 2c + 6b = 27
2p + 3c + 4b = 23
4p + 1c + 8b = 31
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take any 2 equations and eliminate a variable
3p + 2c + 6b = 27
4p + 1c + 8b = 31....multiply by -2
---------------------
3p + 2c + 6b = 27
-8p - 2c - 16b = - 62 (result of multiplying by -2)
--------------------add
-5p - 10b = - 35
Now take one equation, and the other equation that u have not used already, and eliminate the same variable.
4p + 1c + 8b = 31.....multiply by -3
2p + 3c + 4b = 23
---------------------
-12p - 3c - 24b = - 93 (result of multiplying by -3)
2p + 3c + 4b = 23
----------------------add
-10p - 20b = - 70
now take ur 2 equations that u eliminated the c in, and eliminate another variable
-5p - 10b = -35......multiply by -2
-10p - 20b = -70
---------------------
10p + 20b = 70 (result of multiplying by -2)
-10p - 20b = -70
-------------------add
0 = 0
when u get a result such as 0 = 0....this means there is infinite solutions to this problem
Answer : c
I believe this is correct
Answer:
Option 2
Step-by-step explanation:
Number of breakdowns of the photocopiers in year 2011,
A1 = 15
A2 = 21
B1 = 34
B2 = 32
B3 = 23
Option (1)
A1 had just under a half the number of breakdowns compared to photocopier B3.
Half of B3 = 12
And A1 = 15
Therefore, A1 > B3
So the statement is False.
Option (2)
A1 had just under 50% of the breakdowns compared to photocopier B2
50% of the breakdowns of B2 = 16
A1 = 15
So, A1 < 50% of B2
Statement (2) is True.
Option (3)
A1 had more than 25 extra breakdowns compared to B1.
A1= 15
B1 = 34
A1 < B1
Therefore, statement is False.
Option (4)
A1 had 6% less breakdowns than photocopier A2.
A1 = 15
A2 = 21
A2 - A1 = 21 - 15 = 6
Percentage less breakdowns =
= 28.6%
So this Option is False.
Therefore, Option (2) is the correct option.