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4 years ago

I need help fast how do I solve this problem

Mathematics

2 answers:

kirill115 [55]4 years ago

7 0

200 ÷ 10 = 20 × 5 = 100
200 ÷ 40 = 5 × 8 = 40

Marina86 [1]4 years ago

3 0

Number of small fish = (200 / 10) * 5 = 20*5 = 100

Number of large fish = (200 / 40) * 8 = 5*8 = 40

Total number of fish = 140

Ratio small to large fish = 40:100 = 2:5.

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Simplify the expression below 3x² - 5x² + 4x²

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An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.

Lunna [17]

<u>ANSWER</u>

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

See attachment for the graph

<u>EXPLANATION</u>

The standard equation of the vertical ellipse with center at the origin is given by

$\frac{ {x}^{2} }{ {b}^{2} } + \frac{ {y}^{2} }{ {a}^{2} } = 1$

where

${a}^{2} \: > \: {b}^{2}$

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

${a}^{2} - {b}^{2} = {c}^{2}$

$\implies \: 289 - {b}^{2} = 225$

$- {b}^{2} = 225 - 289$

$- {b}^{2} = - 64$

${b}^{2} = 64$

We substitute into the formula for the standard equation to get:

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

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