Answer: the probability that a measurement exceeds 13 milliamperes is 0.067
Step-by-step explanation:
Suppose that the current measurements in a strip of wire are assumed to follow a normal distribution, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = current measurements in a strip.
µ = mean current
σ = standard deviation
From the information given,
µ = 10
σ = 2
We want to find the probability that a measurement exceeds 13 milliamperes. It is expressed as
P(x > 13) = 1 - P(x ≤ 13)
For x = 13,
z = (13 - 10)/2 = 1.5
Looking at the normal distribution table, the probability corresponding to the z score is 0.933
P(x > 13) = 1 - 0.933 = 0.067
Answer:
10. it is correct it is 24
11. 21
Step-by-step explanation:
I could not see the answer but it should look like this:
11.6-3(3-[2-3]-10)-3
6-3(3-[-1]-10)-3
6-3(3-(-1)-10)-3
6-3(4-10)-3
6-3(-6)-3
6-(-18)-3
(6-(-18))-3
24-3
21
Answer:
x = 7
Step-by-step explanation:
A line perpendicular to the x- axis is a vertical line parallel to the y- axis.
The equation of a vertical line is
x = c
where c is the value of the x- coordinates the line goes through
The line goes through (7, 13) with x- coordinate of 7, thus
x = 7 ← equation of perpendicular line
Hello!
Three decimals less then 0.85 are:
1) 0.4
2) 0.5
3) 0.6
I hope it helps!
Answer:
(1)0.39
(2)0.14
(3)0.21
(4)0.26
Step-by-step explanation:
John makes 35% of his free throw shots.
- The probability that John makes his shot =0.35
- The probability that John misses his shot =1-0.35=0.65
Sue makes 40% of her free throw shots.
- The probability that Sue makes her shot =0.4
- The probability that Sue misses her shot =1-0.4=0.6
(1)John and sue both miss their shots
P(John and sue both miss their shots)
=P(John miss his shot) X P(Sue misses her shot)
=0.65 X 0.6 =0.39
(2)John and Sue both make their shots
P(John and Sue both make their shots)
=P(John makes his shot) X P(Sue makes her shot)
=0.35 X 0.4=0.14
(3)John makes his shot and Sue misses hers
P(John makes his shot and Sue misses hers)
=P(John makes his shot) X P(Sue misses her shot)
=0.35 X 0.6=0.21
(4)John misses his shot and Sue makes hers
P(John misses his shot and Sue makes hers)
=P(John miss his shot) X P(Sue makes her shot)
=0.65 X 0.4 =0.26
