1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Goshia [24]
3 years ago
8

Make y the subject of w=x2-2yz

Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

y = (x² - w)/2z

Step-by-step explanation:

w = x² - 2yz

To make y the subject of the formula, we will have

2yz = x² - w

Divide both sides by 2z, we will have

y = (x² - w)/2z

Deffense [45]3 years ago
3 0

Answer:

x^2-W/2z=y

Step-by-step explanation:

The question is based on subject of formula which we will have to change the the letter equating the equation

W=x^2-2yz

And we are to make y the subject of formula

Firstly we will have to substrate x^2 from both sides

W-x^2=2yz

We will now have to look for a way to make y the subject of formula from -2yz ...and to achieve this we will have to divide both sides by -2z.and this will make us to achieve our Target

W-x^2/-2z=y

Yes,the target has been met

But we can solve further by multiplying the fraction by -

-W+x^2/2z=y

Which can also be written as

x^2-W/2z=y

Therefore the final answer is

x^2-W/2z=y

You might be interested in
The function f(x)=5(2)^x was replaced with f(x)+k , resulting in the function graphed below.
ella [17]
In this problem, you have to find the y- intercept of f(x)=5(2)^x. I graphed mine into a graphing calculator. An algebraic way to find it is to input x=0 in the function. The y-intercept is 5.  You can see the y-intercept for the new one is -2. That means we shifted the graph down 7 units. (Vertical Shift down 7)  
k=-7
5 0
3 years ago
Read 2 more answers
If someone help me that be awesome
nevsk [136]
The answer is 12,600,000... hope this helps any :3
4 0
4 years ago
Read 2 more answers
An employee works for $45 hours each week. He is paid $4 per hour for 40 hours per week and $6 per hour for overtime, what is hi
makvit [3.9K]

Answer: $190

Step-by-step explanation:

Normal pay $4 * 40 hours = $160

Overtime $6 * 5 = $30

8 0
3 years ago
Read 2 more answers
How do you calculate a t-test in SPSS?
Sergeu [11.5K]

Answer:

To run an Independent Samples t Test in SPSS, click Analyze > Compare Means > Independent-Samples T Test. The Independent-Samples T Test window opens where you will specify the variables to be used in the analysis. All of the variables in your dataset appear in the list on the left side.

6 0
3 years ago
Crystal estimated that repairs to her car would cost about $100. The cost of repairs was actually $175. Fill in the box with Cry
Feliz [49]

percent error=100 times error/predicted

error=175-100=75

predicted=100

percent error=100 times 75/100=75

the answer si 75% error

7 0
4 years ago
Other questions:
  • Question 16a. Please help. ASAP
    11·2 answers
  • If raisins cost $1.80 a pound. find 1/10 the chefs total cost for 100 pounds of raisins
    15·1 answer
  • Ken spent 1/5 of his allowance on a movie, 3/8 on snacks, and 2/7 on games. If his allowance was $20, how much did Ken have left
    8·2 answers
  • Enrollment in the pta increased by 35% this year. last year there were 160 members in the pta .how many pta members are involved
    6·1 answer
  • A story sells boxes of juice in equal-size packs. Ava bought 18 boxes, Katie bought 36 boxes, and Alexa bought 45 boxes. What is
    9·1 answer
  • Paige and Thuy are on a hill by a river. Paige throws a stone into the river. Her
    13·2 answers
  • Show that the bowtie method can be used to multiply (2x -27)(-x +15)
    11·1 answer
  • Solve the system by substitution. <br> x = 4y - 8<br> 3х — 6у = 12
    8·1 answer
  • Help me please I'm trying to get this donee​
    13·2 answers
  • wo neighboring homeowners, , 2, simultaneously choose how many hours to spend maintaining a beautiful lawn. The average benefit
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!