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Goshia [24]
3 years ago
8

Make y the subject of w=x2-2yz

Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

y = (x² - w)/2z

Step-by-step explanation:

w = x² - 2yz

To make y the subject of the formula, we will have

2yz = x² - w

Divide both sides by 2z, we will have

y = (x² - w)/2z

Deffense [45]3 years ago
3 0

Answer:

x^2-W/2z=y

Step-by-step explanation:

The question is based on subject of formula which we will have to change the the letter equating the equation

W=x^2-2yz

And we are to make y the subject of formula

Firstly we will have to substrate x^2 from both sides

W-x^2=2yz

We will now have to look for a way to make y the subject of formula from -2yz ...and to achieve this we will have to divide both sides by -2z.and this will make us to achieve our Target

W-x^2/-2z=y

Yes,the target has been met

But we can solve further by multiplying the fraction by -

-W+x^2/2z=y

Which can also be written as

x^2-W/2z=y

Therefore the final answer is

x^2-W/2z=y

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An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
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The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

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