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3 years ago

Carlos runs 7 miles in 57 3/4 mins. how fast did he run each mile?

1 answer:

3 0

To find how much minutes Carlos runs each mile, you must first multiply 57.75 by 1 which is 57.75 because 57 3/4 and 57.75 is the same thing. Next, you must divide 57.75 by 7. Therefore, Carlos runs 8.25 minutes a mile.

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Help me please I beg

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As far as I understand A)

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3 years ago

Please help me :)) algebra 2! what are the real roots?

irina1246 [14]

Answer:

Step-by-step explanation:

So we have the equation:

$3(x-4)^\frac{4}{3}+16=64$

First, let's subtract 16 from both sides:

$3(x-4)^\frac{4}{3}=48$

Now, let's divide both sides by 3:

$(x-4)^\frac{4}{3}=16$

Remember that with fractional exponents, we can move the denominator into the root position. Therefore:

$(\sqrt[3]{x-4})^4=16$

Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!

$\sqrt[3]{x-4} =\pm 2$

Cube both sides. Since we're cubing, the plus-minus stays.

$x-4=\pm 8$

Add 4 to both sides.

$x=\pm 8+4$

Calculator:

$x=8+4\text{ or } x=-8+4\\x=12\text{ or } x=-4$

So, our answer is A.

And we're done!

7 0

4 years ago

Help me solve this by multiplication or linar combination please

patriot [66]

X would be equal to 0 while y would be equal to -1
-20(0)+6(-1)=-6
-10(0)-4(-1)=4

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4 years ago

Look at the table representing the growth of the circumference of a tree, and then complete the sentences.

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linear

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3 years ago

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is $\hat p_1$ = 1020/1272 = 85/106 = $0.8\overline {0188679245283}$ ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is $\hat p_2$ = 5343/6238 ≈ 0.8565

c) We have the following two way table;

$\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}$

$The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780$

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

$95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}$

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

$95 \% \ CI \approx 0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155$

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0

3 years ago