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Helen [10]
3 years ago
14

What is 6-2p=p+9 ?Because I don't know it​

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Hey there!

  • Firstly, you have to \bold{simplify} each of the sides of your equation
  • \bold{6-2p-p+9\downarrow}
  • \bold{6+(-2p)=p+9\downarrow}
  • \rightarrow\bold{-2p+6=p+9}
  • Now that you have that  portion out of the way, we could  move on to our second step... which is to \bold{subtract} by the value of  \bold{p} on each of your sides
  • \bold{-2p+6-p-p+9-p\downarrow}
  • \rightarrow\bold{-3p+6-9} (you get this because we solve the particular equation we added above)
  • Thirdly, you have to \bold{subtract} by the number \bold{6} on each of your sides
  • \bold{-3p+6-6=9-6\downarrow}
  • \bold{Cancel:6-6} because it equals to \bold{0}
  • \bold{Keep:9-6} because it brings us closer and closer to the answer of \bold{p}
  • Fourthly, we have to \bold{divide} by  the number \bold{-3} on each of your sides
  • \bold{\frac{-3p}{-3}=\frac{3}{-3}}
  • \boxed{\boxed{\bold{Answer:p=-1}}} \checkmark

Good luck on your assignment and enjoy your day!

~\frak{LoveYourselfFirst:)}

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1. Eyeballing the data, the best fit will be pretty close to a line between the leftmost point and the rightmost point.

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(c-a)(y-b) = (d-b)(x-a)

(28 - 4)(y - 220) = (470 - 220)(x - 4)

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24y - 5280 = 250x - 1000

24y = 250 x + 4280

y = (250/24) x+ (4280/24)

Approximately that's,

y = 10.4 x + 178

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Suppose that a fast food restaurant decides to survey its customers to gauge interest in a breakfast menu. After surveying multi
Harlamova29_29 [7]

Answer:

ME= \frac{Width}{2}=\frac{0.078}{2}=0.039

\hat p =0.688+0.039=0.727

\hat p =0.766-0.039=0.727

Step-by-step explanation:

Assuming that the confidence interval is (0.688; 0.766)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval would be given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

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Use the confidence interval to find the point estimate and margin of error for the proportion

The margin of error is given by :

Me=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And for our case we can find the width of the confidence interval like this:

Width =0.766-0.688=0.078

And the estimation for the margin of error would be given by:

ME= \frac{Width}{2}=\frac{0.078}{2}=0.039

Now we can find th point of estimate adding the margin of error to the lower limit of the interval or subtracting the margin of error to the upper limit, like this:

\hat p =0.688+0.039=0.727

\hat p =0.766-0.039=0.727

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Answer:

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Step-by-step explanation:

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a = 91 yd

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h = 45 yd

Volume = ½*91*60*45

= 122,850 yd³

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