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allsm [11]
3 years ago
15

What is the equation in point slope form of the line that passes through the point

Mathematics
1 answer:
madreJ [45]3 years ago
4 0
All we have to do is get y alone and input our values to see if it makes the statement true.

y - 1 = 3(x + 2)
Add 1 to both sides.
y = 3x + 7

y = 3(1) + 7
y = 3 + 7
y = 10

FALSE

y - 2 = 3(x + 1)
Add 2 to both sides.
y = 3x + 3

y = 3(1) + 3
y = 3 + 3
y = 6

FALSE

y + 1 = 3(x - 2)
Subtract 1 from both sides.
y = 3x - 7

y = 3(1) - 7
y = 3 - 7
y = -4

FALSE

y + 2 = 3(x - 1)
Subtract 2 from both sides.
y = 3x -5

y = 3(1) - 5
y = 3 - 5
y = -2

TRUE

The only equation that makes this statement true is D, y + 2 = 3(x - 1).
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Survey asked eight students about their scores on a history test and whether they studied for the test. The table shows the resu
Rudiy27

Answer:The data for the group that did not study are more spread out than the data for the group that studied.

The data for the group that studied are more clustered around the mean than the data for the group that did not study.

The data for the group that did not study are more clustered around the mean than the data for the group that did study.

Step-by-step explanation:

5 0
3 years ago
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PLEASE HELP ME ILL MARK BRAINLIEST !!!!! spam reported
givi [52]

Answer:

a) -4

b) +343

Step-by-step explanation:

a) 10 shares - loss $40

    1 share --- ?

? = 40 / 10 = 4 decrease

b) each week 7 members increase for 49 weeks

so total increase = 7 * 49 = 343

4 0
3 years ago
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Solve for x.<br> (17x - 23)<br> (&amp;r - 4)*<br> -(3x + 17)
Finger [1]

Answer:

17rx2−23rx−71x+75

Step-by-step explanation:

(17x−23)(xr−4)−(3x+17)

=(17x−23)(xr−4)+−1(3x+17)

=(17x−23)(xr−4)+−1(3x)+(−1)(17)

=(17x−23)(xr−4)+−3x+−17

=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)

=17rx2+−23rx+−71x+75

6 0
3 years ago
Instructions below in the image
Juli2301 [7.4K]

Answer:

y = 17x - 22

Step-by-step explanation:

hope this helps you out!

5 0
3 years ago
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The function intersects its midline at (-1.25,-3) and a maximum point at (0,4) Find a formula for f(x) Give an exact expression.
stellarik [79]

Answer:  y = 7cos(0.4π x) - 3

<u>Step-by-step explanation:</u>

The equation of a cosine function is:    y = A cos(Bx - C) + D    where

  • Amplitude (A) is the distance from the midline to the max (or min)
  • Period (P) is the length of one cosine wave   -->   P = 2π/B
  • Phase Shift (C/B) is the horizontal distance shifted from the y-axis
  • Midline (D) is the vertical shift. It is equal distance from the max and min

<u>Midline (D) = -3</u>

(-1.25, -3) is given as a point on the midline.  We only need the y-value.

<u>Horizontal stretch (B) = 0.4π</u>

The max is located at (0,4) and also at (5, 4).  Thus the period (length of one wave) is 5 units.

P=\dfrac{2\pi}{B}\qquad \rightarrow \qquad 5=\dfrac{2\pi}{B}\qquad \rightarrow \qquad B=\dfrac{2}{5}\pi          →     B = 0.4π

<u>Phase Shift (C) = 0</u>

The max is on the y-axis so there is no horizontal shift.

<u>Amplitude (A) = 7</u>

The distance from the midline to the max is: A = 4 - (-3) = 7

<u>Equation</u>

Input A = 7, B = 0.4π, C = 0, and D = -3 into the cosine equation.

            y = A cos(Bx - C) + D

            y = 7cos(0.4π x - 0) - 3

            y = 7cos(0.4π x) - 3

3 0
3 years ago
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