
the first number must be between 1 and 10 (here is 3.3)
the power (here is 5) is an integer exponent of 10 that indicates how many places the decimal point must be moved to make equation true
Greetings,
n00nst00p :)
The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.
Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.
By the fundamental theorem of calculus,

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so


Answer:
3
Step-by-step explanation:
3
Answer: Pam has 7 and Bill has 11
Step-by-step explanation: