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nasty-shy [4]
3 years ago
8

Determine if each function is linear or nonlinear.

Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0
The last two functions dont curve, so they are linear.
EastWind [94]3 years ago
7 0
3x+y=12 and y=x are linear and the rest are nonlinear
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14/100 in simplest form
Readme [11.4K]
0.14. hope this helps
7 0
3 years ago
Read 2 more answers
5x+6.5=8x-2.5 what does this mean and i would like to know how to solve this equation
Bingel [31]

The answer is x = 3

I hope this helped

6 0
4 years ago
What is the vertex of y = x2 + 2x +2<br> O (1,-1)<br> O (2,-2)<br> O (1, 2)<br> 0 (-1, 1)
fredd [130]

Answer:

vertex = (- 1, 1 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = x² + 2x + 2 ← is in standard form

with a = 1 and b = 2 , then

x = - \frac{2}{2} = - 1

substitute x = - 1 into the equation for y- coordinate of vertex

y = (- 1)² + 2(- 1) + 2 = 1 - 2 + 2 = 1

vertex = (- 1, 1 )

8 0
3 years ago
Evaluate the expression 2ab 3+ 6a 3 - 4ab2 when a=2 and b=4.<br> a.176<br> b.180<br> c.215<br> d.216
Tom [10]
The first step for solving this expression is to insert what a and b stand for into the expression. This will change the expression to the following:
2(2)(4)³ + 6(2)³ - 4(2)(4)²
Now we can start solving this by factoring the expression
2(2 × 4³ + 3 × 2³ - 4 × 4²)
Write 4³ in exponential form with a base of 2.
2(2 × 2^{6} + 3 × 2³ - 4 × 4²)
Calculate the product of -4 × 4².
2(2 × 2^{6} + 3 × 2³ -4³)
Now write 4³ in exponential form with a base of 2.
2(2 × 2^{6} + 3 × 2³ -2^{6})
Collect the like terms with a base of 2.
2(2^{6} + 3 × 2³)
Evaluate the power of 2³.
2(2^{6} + 3 × 8)
Evaluate the power of 2^{6}.
2(64 + 3 × 8)
Multiply the numbers.
2(64 + 24)
Add the numbers in the parenthesis.
2 × 88
Multiply the numbers together to find your final answer.
176
This means that the correct answer to your question is option A.
Let me know if you have any further questions.
:)
5 0
3 years ago
Write the standard form of the quadratic function whose graph is a parabola with the given vertex and that passes through the gi
maks197457 [2]

Answer:

The formula for this quadratic function is x*2 +6x+13

Step-by-step explanation:

If we have the vertex and one point of a parabola it is possible to find the quadratic function by the use of this

y= a (x-h)*2 + K

Quadratic function looks like this

y= ax*2 + bx + c

So let's find the a

y= a (x-h)*2 + K where

y is 13, x is 0, h is -3 and K is 4

13= a (0-(-3))*2 +4

13=9a +4

9=9a

9/9=a

1=a

The quadratic function will be

y= 1(x+3)*2 + 4

Let's get the classic form

(x+3)*2 = (x+3)(x+3)

(x*2+3x+3x+9)

x*2 +6x+13

f(0) = 13

6 0
4 years ago
Read 2 more answers
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