Answer:
1042
Step-by-step explanation:
-38,-8,22,52
The common difference is 52 - 22 = 30
a_1 = -38
a_2 = -38 + 30
a_3 = -38 + 2 * 30
a_4 = -38 + 3 * 30 (notice that the common difference is multiplied by 1 less than the term number)
a_n = -38 + (n - 1)30 (since the term number is n, we multiply the common difference by n - 1)
a_n = -38 + 30(n - 1)
a_37 = -38 + 30(37 - 1)
a_37 = 1042
Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
12000
Just do
120000 divided by 10