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3 years ago

Which fraction expresses 36/80 in lowest terms. A- 9/20 B-18/40 C-4/5 D- 18/20

Mathematics

2 answers:

gladu [14]3 years ago

6 0

B) is the correct answer.

PtichkaEL [24]3 years ago

6 0

Hi there!

To get a fraction in lowest terms you would have to reduce or simplify it. Find the GCD and divide the numerator and denominator by the number. So the GCD is 4 So 36/4 and 804= 9/20

9/20

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17. Which of the following trigonometric functions can be described as a reciprocal trig function?

Nataly [62]

Answer:

Step-by-step explanation:

Reciprocal trig functions are opposite or mirror of the normal trig functions. The normal trig functions are as follows:

Sine = opposite side/hypotenuse

Cosine = adjacent side/hypotenuse

Tangent = opposite side/adjacent side

The reciprocals of the above trig ratios would be

Cosecant = hypotenuse/opposite side

Secant = hypotenuse/adjacent side

Cotangent = adjacent side/opposite side

Therefore, looking at the given options, the trigonometric function that can be described as a reciprocal trig function is

D. sec(0)

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3 years ago

Given the vectors u = <5,-1> and v = <1,12>, find -7u-3v. *

zepelin [54]

You multiply vectors and scalar simply by multiplying each component by that scalar:

$-7u = \langle-35,7\rangle,\quad -3v=\langle -3,-36\rangle$

Finally, you sum two vectors by summing the correspondent coordinates:

$-7u-3v = \langle-35,7\rangle+\langle -3,-36\rangle = \langle-38,-29\rangle$

4 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Consider the eq

Deffense [45]

To solve for x in terms of b, simply treat b as a number, and solve for x as usual: first of all, we expand the left hand side:

$-2bx+10 = 16$

Subtract 10 from both sides:

$-2bx = 6$

Divide both sides by -2b:

$x = \cfrac{6}{-2b} = \cfrac{-3}{b}$

This means that in particular, if we set $b= 3$ , we have

$x = \cfrac{-3}{3} = -1$

5 0

3 years ago

Find a formula for the least squares solution of ax=b when the columns of a are orthonormal1 .

neonofarm [45]

Let $\mathbf A$ be a rectangular $m\times n$ matrix with column vectors $\mathbf a_1,\ldots,\mathbf a_n$ , i.e.

$\mathbf A=\begin{bmatrix}\mathbf a_1&\cdots&\mathbf a_n\end{bmatrix}$

Then we have

$\mathbf A^\top=\begin{bmatrix}\mathbf a_1&\cdots&\mathbf a_n\end{bmatrix}^\top$

and the product of the two is

$\mathbf A^\top\mathbf A=\begin{bmatrix}\mathbf a_1\cdot\mathbf a_1&\mathbf a_1\cdot\mathbf a_2&\cdots&\mathbf a_1\cdot\mathbf a_n\\\mathbf a_2\cdot\mathbf a_1&\mathbf a_2\cdot\mathbf a_2&\cdots&\mathbf a_2\cdot\mathbf a_n\\\vdots&\vdots&\ddots&\vdots\\\mathbf a_n\cdot\mathbf a_1&\mathbf a_n\cdot\mathbf a_2&\cdots&\mathbf a_n\cdot\mathbf a_n\end{bmatrix}$

Because the columns of $\mathbf A$ are orthonormal, we have

$\mathbf a_i\cdot\mathbf a_j=\begin{cases}1&\text{for }i=j\\0&\text{for }i\neq j\end{cases}$

which means $\mathbf A^\top\mathbf A$ reduces to an $n\times n$ matrix with ones along the diagonal and zero everywhere else, i.e.

$\mathbf A^\top\mathbf A=\begin{bmatrix}1&0&\cdots&0\\0&1&\cdots&0\\\vdots&\vdots&\ddots&\vdots\\0&0&\cdots&1\end{bmatrix}=\mathbf I_n$

where $\mathbf I$ denotes the identity matrix. This means the solution to $\mathbf{Ax}=\mathbf b$ is given by

$\mathbf A^\top(\mathbf{Ax})=\mathbf A^\top\mathbf b\implies(\underbrace{\mathbf A^\top\mathbf A}_{\mathbf I})\mathbf x=\mathbf A^\top\mathbf b\implies\mathbf x=\mathbf A^\top\mathbf b$

6 0

3 years ago

12x−5y=−20 y=x+4 x=x=x, equals y=y=y, equals

aksik [14]

Answer:

The solution is (0, 4)

Step-by-step explanation:

Please pay attention to the first two equations and drop the last two:

12x−5y=−20 y=x+4 x=x=x, equals y=y=y should ideally be:

12x−5y=−20

y=x+4

Let's find x. Substitute x + 4 for y in the first equation, obtaining:

12x - 5(x + 4) = -20

Carrying out the indicated multiplication, we get:

12x - 5x - 20 = -20, or 7x = 0

If x = 0 then y must be 0 + 4, or 4.

The solution is (0, 4)

8 0

3 years ago