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Marianna [84]
3 years ago
12

1. A student took 60 minutes to answer a combination of 20 multiple-choice and extended-response questions. She took 2 minutes t

o answer each multiple-choice question and 6 minutes to answer each extended-response question.
a. Write a system of equations to model the relationship between the number of multiple-choice questions (m) and the number of extended-response questions (r).


b. How many of each type of question was on the test? Show your work.


2. A scientist wants to make 6 milliliters of a 30% sulfuric acid solution. The solution is to be made from a combination of 20% sulfuric acid solution and a 50% sulfuric acid solution. (Review "Mixture Problems Resources" for help.)


a. Write a system of equations to model the relationship.


b. How many milliliters of each solution must be combined to make the 30% solution? Show your work.


3. Choose the method of solving (graphing, substitution, elimination) that seems easier to use for the system below. Explain why you made your choice. You do not need to solve the system.


2x-3y=4

2x-5y=-6
Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

1) m=15 and r =5

2) 4 and 2 ml

3) x= 0.5 and y = -1

Step-by-step explanation:

given that m multiple choice questions and r extended response questions.

Also given that a) m+r = total no of questions =20 ... i and

                        2m+6r = total time taken = 60  ... ii

b) Divide second equation by 2, m+3r = 30  ... iii

                                                  m+r  = 20   ... i

Subtract to get 2r =10 or r =5

m = 20-5 = 15

Verify: m+r = 15+5 =20

and     2m+6r = 30+30 = 60 minutes.  

Hence verified

--------------------------------------

2) Let a litres of 20% solution and b litres of 50% solution be mixed

a) Then total volume = 6 ml = a+b  ... i

Resulting solution = 30% of 6 ml = 1.8 = 0.2a+0.5b ... ii

b) Solve i and ii

b = 6-a: substitute in ii.

0.2a + 3-0.5a = 1.8

Or a = 4 ml and b = 2ml

Verify: Total volume = a+b =6ml and

concentration = 0.2(4)+0.5(2) = 1.8 = 30% of 6 ml.

Thus verified

---------------------------------

3) 2x-3y=4 ...i

  2x-5y =6... ii

Because x term has the same coefficient in both the equations, elimination is easier.

i-ii gives 2y =-2 or y =-1

Substitute in i, 2x+3 =4 or x = 0.5

So answer is x = 0.5 and y =1


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Solve the following system of equations:<br> y = 5/4x - 2<br> y = -1/4x + 19<br><br> x = ? and y = ?
Dmitry [639]

Answer:

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Read 2 more answers
How do I solve this, and what is the answer? please and thank you.
vovangra [49]

Answer:

A. (x +8) + (-4x+31)/(x^2+2x+1)

Step-by-step explanation:

When you perform long division of polynomials, the first quotient term is the ratio of the highest-degree terms in the numerator and denominator: x^3/x^2 = x.

This fact eliminates all but choices A and C.

The denominator of the remainder term is the denominator of the original expression, so will be x^2 +2x +1, as shown in choice A.

__

So, simply based on a couple of facts about long division (that you learned in the early elementary grades), you can make the correct choice of answer without actually working the problem in detail.

_____

This is a polynomial long division problem. It is worked in virtually the same way that numerical long division problems are worked: first you find a quotient term, then you multiply that by the divisor and subtract the result from the dividend. The difference is the new dividend. These steps are identical to numerical long division.

For polynomial long division, instead of lining up the digits with the same place value, you line up the terms with the same degree of the variable.

As mentioned above, the quotient term is computed only from the highest-degree terms of dividend and divisor, so that part is actually simpler than for numerical long division.

A dividend that is of lower degree than the divisor is considered to be the remainder. As with numerical long division, it can be expressed as a fraction with the divisor as the denominator.

Numerical example: 18/7 = 2 remainder 4 or 2 4/7.

8 0
3 years ago
(7)(8)(9)<br><br> Geometry<br><br> Check Ans<br><br> 7) s = 15<br> 8) y = 64 x = 99<br> 9) 96
Katyanochek1 [597]
Problem 7: Correct
Problem 8: Correct
Problem 9: Correct

The steps are below if you are curious

===========================================================================================

Problem 7

S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15

I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.

===========================================================================================

Problem 8

First find y
y+116 = 180
y+116-116 = 180-116
y = 64

which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x

x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99

===========================================================================================

Problem 9

With any polygon, the sum of the exterior angles is always 360 degrees

The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96

6 0
3 years ago
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