Answer:
a=2x-b
Step-by-step explanation:
Answer:
7 * 3
7+7+7
3+3+3+3+3+3+3
2+2+2+2+2+2+2+2+2+2+1
(2*10)+1
(10*1)+11....
...and so on
Step-by-step explanation:
I don't know what type of expression you are looking for
Answer:
Low = 72/895
Medium = 112/895
High = 711/895
Step-by-step explanation:
Low = number of low quality products over the total number of products
72 / 72 + 112 + 711
Medium = number of medium quality products over the total number of products
112 / 72 + 112 + 711
High = number of high quality products over the total number of products
711 / 72 + 112 + 711
If my answer is incorrect, pls correct me!
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-Chetan K
Answer:
It should be y=4x-7
Step-by-step explanation:
M is the slope meaning Δx over Δy or rise over run
So if you look at (2,2) and count up to (3,6) the rise is 4 and the run is 1 meaning the slope is 4.
B is the y- intercept so then it would just be -7.
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
