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Ann [662]
4 years ago
14

Jamie's Motor Home Sales currently sells 1,100 Class A motor homes, 2,200 Class C motor homes, and 2,800 pop-up trailers each ye

ar. Jamie is considering adding a mid-range camper and expects that if she does so she can sell 1,500 of them. However, if the new camper is added, Jamie expects that her Class A sales will decline to 850 units while the Class C camper sales decline to 2,000. The sales of pop-ups will not be affected. Class A motor homes sell for an average of $140,000 each. Class C homes are priced at $59,500 and the pop-ups sell for $5,000 each. The new mid-range camper will sell for $42,900. What is the erosion cost of adding the mid-range camper
Business
1 answer:
rusak2 [61]4 years ago
5 0

Answer:

$46,900,000

Explanation:

Calculation for the erosion cost of adding the mid-range camper

Erosion cost = [(1,100 - 850) × $140,000] + [(2,200 -2,000) × $59,500]

Erosion cost =(250×$140,000)+(200×$59,500)

Erosion cost =$35,000,000+$11,900,000

Erosion cost = $46,900,000

Therefore the erosion cost of adding the mid-range camper will be $46,900,000

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The new Fore and Aft Marina is to be located on the Ohio River near Madison, Indiana. Assume that Fore and Aft decides to build
Nataly [62]

Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.

<u>Explanation:</u>

The problem is that of Multiple-server Queuing Model.

Number of servers, M = 2.

Arrival rate, \lambda= 6 boats per hour.

Service rate, \mu= 10 boats per hour.

Probability of zero boats in the system,\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\} = 0.5385

<u>Average number of boats waiting in line for service:</u>

Lq =[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0

= [\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385 = 0.0593 boats.

The average time a boat will spend waiting for service, Wq  =  0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.

The average time a boat will spend at the dock, W =  0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.

4 0
3 years ago
Simba Company’s standard materials cost per unit of output is $10.00 (2.00 pounds x $5.00). During July, the company purchases a
Lelechka [254]

Answer:

A)1192 A

B) 192 A

C)  1000 A

Explanation:

The Question is to Compute Simba Company's Total, Price, and Quantity materials Variances

1) Computation of material Cost Variance

= The Standard Cost - The Actual Cost of the material

= 1,500 units x 2 pounds = 3000 pounds

Standard Cost = 3,000 pounds x $5 = $15,000

Therefore material variance = $15,000 - $16,192 = 1192A

2) The material Rate Variance or the Price Variance

= (Standard Rate - Actual Rate) Actual Quantity

= Actual Rae = $16,192 / 3200 = $5.06

Material Rate Variance = (5- 5.06) x 3,200

= 192 A

3) The material Usage Variance or Quantity variance

= (The Standard Quantity - Actual Quantity) Standard Rate

Standard Quantity = 1,500 Units x 2 Pounds = 3000 pounds

Material Usage Variance = (3,000-3,200) 5

= 1000 A

5 0
3 years ago
Larson Company on July 15 sells merchandise on account to Stuart Co. for $1,000, terms 2/10, n/30. On July 20 Stuart Co. returns
pickupchik [31]

Answer:

b. $588

Explanation:

Terms 2/10, n/30 means that 2% discount for the payment within 10 days and the full amount to be paid within 30 days.

When Larson Company sold merchandise, the following entry was made to recording revenue (sales) and the receivable:

Debit Receivable Account $1,000

Credit Revenue $1,000

On July 20 Stuart Co. returns merchandise, the entry is made to record the decreasing of Receivable Account:

Debit Revenue $400

Credit Receivable Account $400

The balance Receivable Account of Stuart Co. = $1000-$400 = $600

On July 24, Stuart Co. makes the payment, the sales discount was:

$600 x 2% = $12

The amount of cash received = $600-$12=$588

The following entry is made:

Debit Cash: $588

Debit Sales discount: $12

Credit Receivable Account $600

7 0
3 years ago
Lennon, Inc. is considering a five-year project that has an initial outlay or cost of $80,000. The respective future cash inflow
SIZIF [17.4K]

Answer:

26.16%

Explanation:

Internal rate of return is the discount rate that equates the after-tax cash flows from an investment to the amount invested

IRR can be determined using a financial calculator

CO = -80,000

C1 = $15,000

C2 = $25,000

C3 = $35,000,

C4 = $45,000

C 5 = 55,000

IRR = 26.16

To determine IRR using a financial calculator:

1. Input the cash flow values by pressing the CF button. After inputting the value, press enter and the arrow facing a downward direction.

2. After inputting all the cash flows, press the IRR button and then press the compute button.  

4 0
3 years ago
A company had net income of $40,000, net sales of $300,000, and average total assets of $200,000. Its profit margin and total as
kvasek [131]

A company had net income of $40,000, net sales of $300,000, and average total assets of $200,000. The profit margin and total asset turnover ratio are 13.3% each. 1.5.

There are two methods that can be used to calculate return on assets. The first method is to divide the company's net income by its average total assets. The second method is to multiply the company's net profit margin by sales.

Return on assets is calculated by dividing a company's after-tax earnings by total assets. The balance sheet total corresponds to the company's total equity and liabilities. This value can be found on the company's balance sheet.

Learn more about assets at

brainly.com/question/25746199

#SPJ4

4 0
2 years ago
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