Answer: The answer is B. Hope this helps :)
Step-by-step explanation:
Answer:
The insect population after 6 days is of 1639 insects.
Step-by-step explanation:
A population of insects increases at a rate 230 + 8t + 0.9t2 insects per day
This means that 
The population of insects after x days is given by:

So



In which K is the initital population(which is 50). So

After 6 days:

Rounding to the nearest insect, 1639
The insect population after 6 days is of 1639 insects.
You rounded your number to the 100,000's (hundred thousands)
Answer:
It is pi over nine, the one that your cursor is on. Forgive me if I am wrong
Step-by-step explanation:
Answer:
thank me
Step-by-step explanation: