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poizon [28]
2 years ago
6

Find the equation of the line with slope m

Mathematics
1 answer:
sukhopar [10]2 years ago
4 0

Answer:

<em>y = - </em>\frac{1}{2}<em> x - 4 </em>

Step-by-step explanation:

( x_{1} , y_{1} )

y -  y_{1} = m ( x - x_{1} )

~~~~~~~~~~~~~~~~~

m = - \frac{1}{2}

( - 10, 1 )

y - 1 = - \frac{1}{2} [ x - ( - 10 )]

y - 1 =  - \frac{1}{2} x + ( - \frac{1}{2} )(10)

<em>y = - </em>\frac{1}{2}<em> x - 4</em>

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Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
Factorize 12x² + 15xy​
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Answer:

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Step-by-step explanation:

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Answer:

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The points L, M, N and O all lie on the same line segment, in that order, such that the ratio of LM : MN : NO is equal to 3 : 1
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Answer:

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Step-by-step explanation:

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and solve, see image.

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When solving a system of two linear equations
soldier1979 [14.2K]

Answer:

When both equations have the same slope, but not the same y-intercept, they'll be parallel to each other and no intersections means no solutions. When both equations have different slopes than regardless of the y-intercept they'll intersect for certain, therefore it has exactly one solution.

Step-by-step explanation:

Got this from google hope it helps

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