Answer:
Step-by-step explanation:
![\left[\begin{array}{ccc}7&31\\142&19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%2631%5C%5C142%2619%5Cend%7Barray%7D%5Cright%5D)
= 7(19) - 142(31) = <em>- 4269</em>
![\left[\begin{array}{ccc}7&11&21\\55&-8&2\\-16&-1&-9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%2611%2621%5C%5C55%26-8%262%5C%5C-16%26-1%26-9%5Cend%7Barray%7D%5Cright%5D)
= 7(- 8)(- 9) + 11(2)(- 16) + 21(55)(- 1) - 21(- 8)(- 16) - 7(2)(- 1) - 11(55)(- 9) = <em>1768</em>
![\left[\begin{array}{ccc}9.07&6.02&2.01\\-30.7&2.5&3.5\\3.55&-1.1&2.35\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9.07%266.02%262.01%5C%5C-30.7%262.5%263.5%5C%5C3.55%26-1.1%262.35%5Cend%7Barray%7D%5Cright%5D)
= 9.07(2.5)(2.35) + 6.02(3.5)(3.55) + 2.01(- 30.7)(- 1.1) - 2.01(2.5)(3.55) - 9.07(3.5)(- 1.1) - 6.02(- 30.7)(2.35) = <em>647.3561</em>
Answer:
2.5
Step-by-step explanation:
5/2=2.5
half of 2 is 1 so for 1 cup of coco has 2.5 tbs of coco.
So you need to solve for the x and y values...I personally would use a graph. The is this website called desmos, it can help you with this kind of problem. You can see that the green point which is (10, 44) is on the line.. Lets check our work...
y = 4x + 4
44 = 4(10) + 4
44 = 40 + 4
44 = 44
This is your answer. I hope this helps love! :)
If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
Answer:
I think it is the last one .
Step-by-step explanation:
Hope this helps!
Sorry if I'm wrong.
