To solve this problem you must apply a theorem called: Intersecting secant theorem. The proccedure is shown below:
1) For the figure shown on the left:
(5)(x+5)=(6)(4+6)
5x+25=60
5x=60-25
x=35/5
x=7
2) For the figure shown on the right:
(3)(3+5)=(4)(x+4)
24=4x+16
24-16=4x
8=4x
8/4=x
x=2
Answer:
b
Step-by-step explanation:
The difference between price is 4 dollars and 4 dollars is 10 percent of 40, therefore it changes by 10%
A = 133; b = 31; c = 82; d = 64.
Opposite angles in an inscribed quadrilateral are supplementary; this means that d + 116 = 180. Subtracting 116 from both sides, we have d = 64.
By the same theorem, c + 98 = 180; subtracting 98 from both sides, we have c = 82.
Inscribed angles are equal to 1/2 the measure of the intercepted arc. Using this, we have
116 = 1/2(a+99)
Multiplying both sides by 2, we have
232 = a+99
Subtract 99 from both sides:
232 - 99 = a + 99 - 99
133 = a
We also have that
82 = 1/2(133+b)
Multiplying both sides by 2, we have:
164 = 133 + b
Subtract 133 from both sides:
164 - 133 = 133 + b - 133
31 = b
Givens
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b = 13
h = 9
Area = b*h
Area = 13*9 = 117 square in
Trapezoid
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Givens
b1=9
b2 = 15
h = 14
Area = (b1 + b2)*h/2
Area = (9 + 15)* 14/2
Area = 24 * 14 / 2
Area = 336/2
Area = 168 square inches.
Rhombus
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I can't see the second number I'll make one up. Redo the questioin and put a the number in
Area = 1/2 * d1 * d2
d1 = 18
d2 = 12 substitute what it really says here.
Area = 1/2 * 18 * 12
Area = 108
Je vous aiderais... mais y a-t-il une question pour elle ?
