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Darya [45]
3 years ago
11

What number is the opposite of the number 0

Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0

Answer:

it is the second one, number zero does not have an opposite

Step-by-step explanation:

RUDIKE [14]3 years ago
4 0

Answer:

B does not have an opposite number

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While standing in front of the school
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Answer:

Step-by-step explanation:

what do u see!????????

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2 years ago
Which of these tables is a ratio table?
OverLord2011 [107]

Answer:

its the second one from the left

1×4=4

3×4=12

6×4=24

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2 years ago
You are working with a quadratic equation and construct the following table.
Alecsey [184]

Answer:

a) Vertex is at (-3, -1)

b) y-intercept is at (0,8)

c) x intercept is at (-4,0) and (-2,0)

d) x=-3

Step-by-step explanation:

We know the vertex is the lowest or highest part of a parabola meaning all the points are reflected across.  It is the only y value without a matching pair

E.x. -1 and 1, -3 and 3

The only point without a corresponding y value is (-3,-1) therefore the vertex is at (-3,-1)

The y-intercept is where the parabola meets the y axis or the x value is equal to 0, we just have to find when x = 0 to find the y intercept

y intercept: (0,8)

For the x intercept's it is just the reverse, you need to find where the parabola crosses the x axis or when y = 0

x intercept 1:(-4,0)

x intercept 2: (-2,0)

The axis of symmetry is also the x coordinate of the vertex which is 3 so

x = 3

6 0
3 years ago
If f:x =
kodGreya [7K]

Answer:

4455587111*#654..++4756##8008/+.+=///=!558887425

6 0
3 years ago
two telephone calls come into a switchboard at times that are uniformly distributed in a fixed one-hour period. assume that the
AleksandrR [38]

We wil assume a variable x to be the total number of calls received by the switchboard.

The question also says to assume that the calls were made independently.

Given:

Calls are independent.

Calls are uniformly distributed over a 1 hour period.

Ans (a). The calls are distributed uniformly over 1 hour, hence: (0, 1).

So we have,

f1(x1) = 1

f2(x2) = 1

X1 and X2 are considered to be independent of each other. Hence,

f(x1,x2) = f1 (x1) f2 (x2)

f(x1,x2) = 1 (1)

f(x1,x2) = 1

Thus,

P(X1 <= 0.5; X2 <= 0.5) = ∫0.50 ∫0.50 f(x1,x2) dx2 dx1

= ∫^0.5 0 ∫^0.5 0 (1) dx2 dx1

= ∫^0.5 0 (x2^0.5 0) dx1

= ∫^0.5 0 (0.5 - 0) dx1

= 0.5 ∫^0.5 0 dx1

= 0.5 (x1^0.5 0)

= 0.5 (0.5 - 0)

= 0.25

Therefore, the probability that the calls were received within the first 30 minutes or first half hour is 0.25.

Ans (b). Steps 1 and 2 are the same as the above answer.

Probability = [∫^11/12 0 ∫^x1 + 1/12 x1 1dx2 dx1] + [∫^1 1/12 ∫^x1 x1-1/12 1dx2 dx1

= [∫^11/12 0 (x2 ^x1+1/12 x1 dx1] + [∫^1 1/12 (x2 ^x1 x1-1/12 dx1)]

= [∫^11/12 0 (x1 + 1/12 -x1) dx1] + [∫^1 1/12 (x1 - x1 + 1/12) dx1]

= [(1 + x1/12 - 1) ^11/12 0] + [( 1 - 1 + x1/12) ^1 1/12]

= 11/144 + 11/144

= 0.1528

Therefore, the probability that the calls were received within five minutes of each other is 0.15.

Find more from: brainly.com/question/18125359?referrer=searchResults

#SPJ4

7 0
9 months ago
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