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jek_recluse [69]
2 years ago
14

A car is traveling on a highway. The distance (in miles) from its destination and the time (in hours) is given by the equation d

= 420 minus 65 t. What is the practical meaning of the d-intercept? a. Initially the car is 355 miles from its destination. b. Initially the car is 420 miles from its destination. c. Initially the car is 65 miles from its destination. d. Initially the car is 485 miles from its destination.
Mathematics
1 answer:
blondinia [14]2 years ago
3 0

Answer:

d–intercept is simply the value of t when d equals zero. Which this case is when he reaches it his destination.

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A man buys 6 ½ of petrol daily. How many litres of petrol does he purchase in six days​
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What are the domain and range of this function? {(-1,6),(2,0), (9,–3),(-4,6)}​
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8 0
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!!!please for the love of God help me!!!
Grace [21]
<h3>Given :-</h3>

\\

  • x=y-1
  • x+2y=8

\\

<h3>To find:</h3>

\\

  • Value of x
  • Value of y

\\

<h3>Solution:-</h3>

Let say it is first equation:-

x=y-1. . . . (1)

and this is second equation:-

x+2y=8 . . . . (2)

\\  \\

Simplifying 1 equation:-

  • x = y - 1
  • x +1 = y
  • y = x + 1

Put this value of y in second equation.

\\

\dashrightarrow \sf \: x+2y=8

\\

\dashrightarrow \sf \: x+2(x + 1)=8

\\

\dashrightarrow \sf \: x+2x +2=8

\\  \\

\dashrightarrow \sf \: 3x +2=8

\\  \\

\dashrightarrow \sf \: 3x=8 - 2

\\  \\

\dashrightarrow \sf \: 3x=6

\\  \\

\dashrightarrow \sf \: x=6 \div 3

\\  \\

\dashrightarrow \sf \: x= \bf2

\\

to find value of y :-

y = x + 1

y = 2 + 1

y = 3

\\

verification:-

\\

1 equation:-

x = y - 1

put value of x and y

2 = 3 - 1

2 = 2

LHS = RHS

Hence verified!

\\

2 equation:-

\\

  • x+2y=8

put value of x and y

  • 2 + 2 × 3 = 8
  • 2 + 6 = 8
  • 8 = 8

LHS = RHS

Hence verified!

\\

Both equation verified!

.°. value of x and y is 2 and 3 respectively

7 0
2 years ago
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